The power of result (1) (- 2) is expressed as the power of 2009 + the power of (- 2) is expressed as the power of 2010=_______ The quintic power of (- 2 / 3) × (- 2 / 9) (1) 2009 power of (- 2) + 2010 power of (- 2)=_______ The fifth power of (- 2 / 3) × (- 2 / 9)=_______ Urgent request And write the process and reasons

The power of result (1) (- 2) is expressed as the power of 2009 + the power of (- 2) is expressed as the power of 2010=_______ The quintic power of (- 2 / 3) × (- 2 / 9) (1) 2009 power of (- 2) + 2010 power of (- 2)=_______ The fifth power of (- 2 / 3) × (- 2 / 9)=_______ Urgent request And write the process and reasons

2^2009 (1/3)^10

-2-3-5-6-8-9-.-2009-2010=?

-2-3-5-6-8-9-…… -2009-2010
=1-1-2-3-.-2009-2010
=1-（1+2+3+...+2009+2010）
=1-2011 × 2010 △ 2 (formula: sum of the first item + a certain item multiplied by the number of items divided by 2)
=1-2011×1005
=-2021054

If G (x) = 1-2x, f [g (x)] = 1 − x2x2 (x ≠ 0), then f (12) is equal to ()
A. 15B. 1C. 3D. 30

Let g (x) = 12, we get 1-2x = 12, and the solution is x = 14. The solution is x (12) = f [g (14)] = 1 − (14) 2 (14) 2 = 1516116 = 15

Given that G (x) = 1-2x, f [g (x)] = 1-x2-x2 (x is not equal to 0), then Fen (1-2) is equal to?

Let g (x) = 1-2x = 1 / 2
x=1/4
So f (1 / 2) = [1 - (1 / 4) & sup2;] / (1 / 4) & sup2; = 15

If G (x) = 1 + 2x and f [g (x)] = 1 + x2 / X2, then f (2) =?

Let g (x) = 2
Then 1 + 2x = 2
x=1/2
So f (2) = [1 + (1 / 2) & # 178;] / (1 / 2) & # 178; = 5

If f (x-1) = 1 / (x2-1), then what is f (x) equal to?
That two is square

Let t = X-1, then x = t + 1, and substitute it into the solution to get f (x) = 1 / (x + 2x)

F (1-x / 1 + x) = (1-x2 / 1 + x2), what is f (x) equal to

f(1-x/1+x)=（1-x2/1+x2） f=（1-x2/1+x2）/(1-x/1+x) f=（1-2x）（1+X）/（1+2x）（1-X） f=1-x-2X/1+X-2X

F (x) = x + 5 (x is less than or equal to - 1) and X2 + 1 (- 1)

1 when x ≤ - 1
X + 5 = 3, x = - 2 meet the condition
2 Dang - 1

If f (x) is known to be an odd function, and if x > 0, f (x) = x2 + 1X, then f (- 1) = ()
A. 2B. 1C. 0D. -2

∵ if f (x) is known to be an odd function, and if x > 0, f (x) = x2 + 1X, then f (- 1) = - f (1) = - (1 + 1) = - 2, so D

How much does (x + 1) (x-1) (x2-x + 1) (x2 + X + 1) equal

(x+1)(x-1)(x2-x+1)(x2+x+1)
=[(x+1)(x^2-x+1)][(x-1)(x^2+x+1)]
=(x^3+1)(x^3-1)
=x^6-1