-What is the 2010 power of 1 + - 4 × & # 188; 2009 power!

-What is the 2010 power of 1 + - 4 × & # 188; 2009 power!

(-1)^2010 + (-4)^2010 × (1/4)^2009
＝1^2010 + 4^2009 × 4 × (1/4)^2009
＝1 + (4×1/4)^2009 ×4
＝1 + 1^2009 ×4
＝1 + 4
＝5

Simple calculation of 2008 × 2008 / 2009
RT
Wrong number, 2008 out of 2009

2008 ×2008/2009
=2008×(2009-1)/2009
=2008×(2009/2009-1/2009)
=2008×(1 -1/2009)
=2008- 2008/2009
=2007 and 2009

Simple calculation of 2008 + 2008 and 2008 / 2009

2008
2008+2008——
two thousand and nine
two thousand and eight
=2008+2008+——
two thousand and nine
one
=2008+2008+2009-——
two thousand and nine
one
=2008×3+1- ——
two thousand and nine
two thousand and eight
=6024+——
two thousand and nine
two thousand and eight
=6024——
two thousand and nine

2008 - (2008 / 2009) how to simplify the calculation?

2008-(2008/2009）
=2007+1-2008/2009
=2007+2009/2009-2008/2009
=2007+1/2009
=2007 and 2009

Given x x 2 -- = 7, finding the values of X 2-x + 1 x 4 + x 2 + 1 x 2 and x 4 are quadratic and quartic of X
Known x x2
——————=7. Find the value of
x2-x+1 x4+x2+1
X2 and X4 are quadratic and quartic of X
Double the reward for the right answer!

The solution transformation formula is (x ^ 2 - x + 1) / x = 1 / 7, that is, x + 1 / x = 8 / 7 square of both sides, so x ^ 2 + 2 + 1 / x ^ 2 = 64 / 49 (x ^ 4 + x ^ 2 + 1) / x ^ 2 = x ^ 2 + 1 + 1 / x ^ 2 = 64 / 49 - 1 = 15 / 49, so x ^ 2 / (x ^ 4 + x ^ 2 + 1) = 49 / 15

Given that xx2-x + 1 = 7, then x2x4 + x2 + 1 = 7___ ．

From the meaning of the question: x2-x + 1x = 17, that is, x + 1x = 87, X4 + x2 + 1x2 = x2 + 1x2 + 1 = (x + 1x) 2-2 + 1 = 1549, the reciprocal is x2x4 + x2 + 1 = 4915

Given x x 2 − x + 1 = 13, find the value of X 2x 4 + x 2 + 1

∵ XX2 − x + 1 = 13, ∵ x2 = 4x-1, ∵ original formula = 4x − 1 (4x − 1) 2 + 4x = 4x − 116x2 − 8x + 1 + 4x = 4x − 116x2 − 4x + 1 = 4x − 116 (4x − 1) − 4x + 1 = 4x − 115 (4x − 1) = 115

Known as | x1-1 | + | x2-2 | + | x3-3 | + +|X2002-2002 | + | x2003-2003 | = 0, find the algebraic formula 2x1 − 2x2 − The value of − 2x2002 + 2x2003

∵|x1-1|+|x2-2|+|x3-3|+… +|x2002-2002|+|x2003-2003|=0，∴x1=1，x2=2，x3=3，… ，x2002=2002，x2003=2003，∴2x1−2x2−… −2x2002+2x2003=2-22-… -22002+22003=22003-22002-… -22+2=22002-22001… -22+2=22001-… -22+2… =22 + 2 = 4 + 2 = 6 The value of − 2x2002 + 2x2003 is 6

1 + X + x2 + X3 + X4 = 0, then 1 + X + x2 + X3 + X4 + +x2004=?
Note: 2342004 means square

1+x+x2+x3+x4+…… +x2004=1+x+x^2+x^3+x^4+x^5+..+x^2004=0+x^5(1+x+x^2+x^3+x^4)+x^10+..+x^2004=0+x^10(1+x+x^2+x^3+x^4)+x^15+..+x^2004=..=0+x^2000(1+x+x^2+x^3+x^4)=0

X2-3x + 1 / 4 x = 1 / 4 to find the value of x4-2x2 + 1 / 1 x2

x/(x^2-3x+1)=1/4
1/(x-3+1/x)=1/4
4=x+1/x-3
x+1/x=7
(x+1/x)^2=49
x^2+1/x^2+2=49
x^2+1/x^2=47
x^2/(x^4-2x^2+1)
=1/(x^2-2+1/x^2)
=1/(47-2)
=1/45