How to calculate: 2008 * 2008 / 2009?

How to calculate: 2008 * 2008 / 2009?

Original formula = (2009-1) ^ 2 / 2009 = (2009 ^ 2-2 * 2009 + 1) / 2009 = 2009-2 + 1 / 2009 = 2007 + 1 / 2009
1 / 2009 minimum = 0, original = 2007

Calculation: 2512008 × 2009 + 2512009 × 2010=______ ．

2512008 × 2009 + 2512009 × 2010, = 251 × (12008 × 2009 + 12009 × 2010), = 251 × (12008-12009 + 12009-12010), = 251 × 22008 × 2010, = 18040; so the answer is: 18040

17 out of 12 times 5 out of 34

About 17 and 34
17/12 * 5/34
=1/12 * 5/2
=5/24

17/12*5/34*3/4
If you can make it simple, make it simple

=(17/34)*(5/4)*(3/12)
=(1/2)*(5/4)*(1/4)
==5/32

Given that the polynomial 2x5 + (M + 1) X4 + 3x - (n-2) x2 + 3 does not contain the even power of X, can you find the value of 2m + n?

The solution is m = - 1, n = 2, 2m + n = 2 × (- 1) + 2 = 0

If the sum of MX2 power + 2nx-3 and (3m + 4) x2 power - (n + 2) x + 4 is independent of the value of X, then the value of - (- M) n power is ()
The value of 2x2 power + ax-y + 6) - (2abx2 power - 3x + 5y-1) has nothing to do with the value of letter X. find the value of algebraic formula 3 (A2 power - 2ab-b2 power) - (4a2 power + AB + B2 power)

If the sum of MX2 power + 2nx-3 and (3m + 4) x2 power - (n + 2) x + 4 is independent of the value of X, then the value of - (- M) n power is ()
Sum of polynomials = (M + 3M + 4) x ^ 2 + (2n-n-2) x + (4-3) = (4m + 4) x ^ 2 + (n-2) x + 1
Since and have nothing to do with the value of X, the coefficient before x is equal to zero
That is: 4m + 4 = 0, n-2 = 0
We get: M = - 1, n = 2
-(-m)^n=-(+1)^2=-1
The value of 2x2 power + ax-y + 6) - (2abx2 power - 3x + 5y-1) has nothing to do with the value of letter X. find the value of algebraic formula 3 (A2 power - 2ab-b2 power) - (4a2 power + AB + B2 power)
Original formula = (2x ^ 2-2abx ^ 2) + (AX + 3x) - y + 6-5y + 1
=(2-2ab)x^2+(a+3)x-6y+7
If the value of X is independent of the value of X, there are:
2-2ab=0
a+3=0
A = - 3, B = - 1 / 3
3 (A2 power - 2ab-b2 power) - (4a2 power + AB + B2 power)
=3a^2-6ab-3b^2-4a^2-ab-b^2
=-a^2-7ab-4b^2
=-(-3)^2-7*(-3)(-1/3)-4*(-1/3)^2
=-9-7-4/9
=-16 and 4 / 9

Find the master to solve the eighth grade math problem if x + 1 / x = 3 find the value of x2 / X4 + x2 + 1
X4 + x2 + 1 is the whole (denominator)

x^2/x^4+x^2+1
=1/x^2+x^2+1
x+1/x=3
(x+1/x)^2=3^2=9
x^2+1/x^2+2=9
x^2+1/x^2=7
Then x ^ 2 + 1 / x ^ 2 + 1 = 8
That is, x ^ 2 / x ^ 4 + x ^ 2 + 1 = 8

Given x2-1 = 4x, find the value of X4 power + 1 / X4 power

x²-1=4x
x-1/x=4
(x-1/x)²=16
x²+1/x²=18
x^4+1/x^4
=(x²+1/x²)²-2
=18²-2
=322

Prove that the square of 2005 + the square of 2006 * the square of 2005 + the square of 2006 is equal to the square of an integer

2005^2+2006^2*2005^2+2006^2=2005^2+(2005+1)^2*2005^2+2006^2=2005^2+2005^4+2*2005^3+2005^2+2006^2=2005^4+(2*2005+2)*2005^2+2006^2=2005^4+2*2006*2005^2+2006^2=(2005^2+2006)^2

Suppose that the lengths of a, B and C on the three sides of the triangle ABC are natural numbers, and a is greater than or equal to B, greater than or equal to C, and B = 10. How many triangles are there?
Please help me

Right triangle 3.4.5