If natural numbers a and B satisfy the following conditions: a-1b = 1182, a: B = 7:13, then a + B=______ ．

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It is known that 1 / A-1 / b = 5 / 24, where a and B are non-zero natural numbers, then what is a × B equal to? A, and what are B respectively?

Note that there are two
1) 5/24
=8/24-3/24
=1/3-1/8
a=3, b=8
ab=3x8=24
2) 5/24
=6/24-1/24
=1/4-1/24
a=4, b=24
ab=4x24=96

1 / 24 is equal to 1 / 24 of a plus 1 / 24 of B. If a and B are two different natural numbers, the minimum sum of a and B is ()
Why?

36+72=108

If one fifth of a is equal to B plus one fifth of a is equal to one ninth, a and B are both natural numbers, and a is not equal to zero, then what is B

One in a is one in nine
Then a = 9
B plus a fifth is one ninth
9/(b+5)=1/9
b+5=81
b=76

17 out of 42 is equal to 6 out of A-7 out of B, and ab is a natural number, so what is the minimum difference between a and B!

17/42=a/6-b/7
=7a/42-6b/42
=(7a-6b)/42
∴17=7a-6b
When a = 5 and B = 3, it is satisfied
In this case, A-B = 2

If the natural number AB satisfies that 7 / a minus 9 / b equals 5 / 66 and a: B = 3:11, what is a + B equal to

7/A-9/B=5/66
A:B=3:11
Then a = 3 / 11 * B
Substituting a = 3 / 11 * B into
So, B = 220
Substituting, B = 220
Well, a = 60
Then a + B = 280

a. B represents two non-zero natural numbers, and 1 / a minus 1 / B is equal to 1 / 30

1/a-1/b=1/30
1/a-1/b=1/5*6
1/a-1/b=1/5-1/6
So:
a=5,b=6

If 1 / 24 = 1 / A + 1 / B, a and B are two different natural numbers, then the sum of a and B is the smallest（
Write the formula, and why
Or I won't

Basic inequality
1 / A + 1 / B is greater than or equal to 1 / AB under 2 radicals
So 1 / 24 is greater than or equal to 2 root sign 1 / ab

One in 24 is equal to one in a plus one in B. If a and B are two different natural numbers, what is the minimum sum of a and B

a. The minimum sum of B is 36 + 72 = 108

If natural numbers a and B satisfy the following conditions: a-1b = 1182, a: B = 7:13, then a + B=______ ．