What is 12 times 13 times 2

three hundred and twelve

12 times 13 is equal to? Is that right?
1 times 1 equals 1 (head multiplication), 2 plus 3 equals 5 (tail addition), 2 times 3 equals 6 (tail multiplication), so it's 156? Is this a quick calculation? The multiplication formula of more than ten times more than ten is: head multiplication, tail addition, tail multiplication

Exactly
However, this only applies to the case of no carry

How much is one times 60%?

0.6

What is 0.75:1?

0.75 or 75 / 100

Q: a two digit number minus three times the sum of its digits is 23. The quotient of this two digit number divided by the sum of its digits is 5, and the remainder is 1. What is this two digit number?

Let two digits be AB, then 10A + B - (a + b) * 3 = 23, that is, 7a-2b = 23
10A + B-1 = 5A + 5b, that is 5a-1 = 4B
The solution is a = 5, B = 6
This two digit number is 56

A two digit number, minus three times the sum of its digits, results in 23; the quotient of the two digit number divided by the sum of its digits is 5, and the remainder is 1,
Find two digits

Let ten bits be x and the other bits be y
10x+y-3(x+y)=23
10x+y=5(x+y)+1

A two digit number, minus three times the sum of its digits, results in 23. The quotient of this two digit number divided by the sum of its digits is 5, and the remainder is 1. What are these two digits?

Let X be the ten digit number of this two digit number, and y be the number of each digit. According to the meaning of the question, we get 10x + y − 3 (x + y) = 2310 x + y = 5 (x + y) + 1, and the solution is x = 5Y = 6, so this two digit number is 56. A: this two digit number is 56

The sum of four numbers is 160, the first number plus 3, the second number minus 3, the third number multiplied by 3, the fourth number divided by 3, the results are all equal, find these four numbers

Let a, B, C and d be four numbers
Then a + 3 = B-3
b=a+6
a+3=3c
c=(a+3)/3
a+3=d/3
d=3a+9
That is, a + A + 6 + (a + 3) / 3 + 3A + 9 = 160
The solution is a = 27
Then a = 27, B = 33, C = 10, d = 90

Divide 99 into four numbers, so that the first number plus 2, the second number minus 2, the third number multiplied by 2, the fourth number divided by 2, the results are equal. How do you think we should divide 99 into four numbers?

Let the equal number be x, then the remainder is (X-2), (x + 2), X2, 2x. From the meaning of the question, we can get: (X-2) + (x + 2) + x2 + 2x = 99, and the solution is: x = 22, then X-2 = 20, x + 2 = 24, X2 = 11, 2x = 44, so we should divide 99 into four numbers: 20, 24, 11, 44

Divide 160 into the sum of four numbers, so that the first number of 160 is added by 3, the second number is subtracted by 3, the third number is multiplied by 3, the fourth number is divided by 3, and the results are equal. How should we divide 160
I want to include the process, and not the process that is difficult to understand. Every process needs to, and can't wait for one step,

Suppose "the first number plus 3, the second number minus 3, the third number multiplied by 3, and the fourth number divided by 3, all the equal results are x"
The first number: x-3
The second number: x + 3
Three: X △ 3
... 4.: 3x
There are: (x-3) + (x + 3) + (x △ 3) + (3x) = (16 / 3) x = 160
x=30
So the four numbers are 27, 33, 10 and 90

What is 12 times 13 times 2