(1 times 4) 1:1 plus (4 times 7) 1:1 plus (7 times 10) 1:1. Plus (97 times 100) 1:1 equals (process)

(1 times 4) 1:1 plus (4 times 7) 1:1 plus (7 times 10) 1:1. Plus (97 times 100) 1:1 equals (process)

0.331/(1x4)+1/(4x7)+1/(7x10)+~+1/(97x100)=(1/3)x(1-1/4)+1/3x(1/4-1/7)+1/3x(1/7-1/10)+~+1/3x(1/97-1/100)=1/3x(1-1/4+1/4-1/7+1/7-1/10+~+1/97-1/100)=1/3x(1-1/100)=33/100=0.33

If f (3 ^ x) = 4xlog2 (3) + 233, then f (2) + F (4) + F (8) +. + F (2 ^ 8) is equal to

f(3^x)=4xlog2(3)+233
=log2[2^233*(3^x)4]
Let t = 3 ^ X
f(t)=log2(t^4)+233
The function expression of F (x) is as follows:
f(x)=log2(x^4)+233
f(2)+f(4)+...+f(2^8)
=233*8+log2[2^(1+2+...+8)]^4
=1864+log2[2^(8*9/2)]^4
=1864+log2(2^144)
=1864+144
=2008

If f (3 ^ x) = 2xlog2 (3) + 10, then f (2) + F (4) + F (8) + +The value of F (2 ^ 8) is equal to
^It's a power. There's no multiply sign

F (3 ^ x) = 2xlog2 (3) + 10F (3 ^ x) = 2log2 (3 ^ x) + 10 is to move X after log and take 3 ^ x as a whole, that is, f (x) = 2log2 (x) to calculate f (2) + F (4) + F (8) + +f(2^8）=2log2(2)+10+2log2(4)+10+…… +2log2 (2 ^ 8) I calculated 152, please do it yourself

What is minus 34 times 5?

Negative 170

[(X-10) times 75 + 900] divided by x = 80, this equation is solved

[(x-10)×75+900]÷X=80
(x-10)×75+900=80X
75X-750+900=80X
75X+150=80X
80X-75X=150
5X=150
X=30

13 divided by 4 = 24 ratio () = () percentage
Or teach me the way!

13 divided by 4 = 24 (96 / 13) = (325%)

Given that the greatest common divisor of a and B is 6, and AXB = 126, what is a + B?

18 and 42. 126 divided by 6 = 21 is the product of two coprime, which is 3 and 7, so it's 3 * 6 = 18, 7 * 6 = 42, 18 + 42 = 60

1 divided by 3 equals 0.33333 ~ but why does 0.33333333 ~ multiply by 3 not equal to 1

Is = 1, if it is an infinite cycle, it involves the limit problem in higher mathematics, and the limit is equal to 1

1 / 3 = 0.333333 cycle? 3 * 0.333333 cycle = 0.999999 cycle? 3 * 1 / 3 = 1 1 = 0.999999 cycle?
1 / 3 = 0.333333 cycle
3 * 0.333333 cycle = 0.99999 cycle
3*1/1=1
1 = 0.999999 cycle
?

0.9999999. It's actually 0.9 + 0.09 + 0.009 + 0.0009 +. It's going on
It is an equal ratio sequence with the first term of 0.9 and the common ratio of 0.1
The sum of the first n terms of this sequence is: 0.9 * (1-0.1 ^ n) / (1-0.1) = 1-0.1 ^ n
And the value of the infinite circular decimal 0.99999. Is the value of the proportional sequence when n tends to infinity (because 0.99999... Has infinitely many digits!)
According to the limit, when n tends to infinity, the value of 1-0.1 ^ n is 1
So, 0.99999999. = 1

How much is 999999 multiplied by 999999 plus 1999999?

9999999*9999999+1999999
=(10^6-1)^2+1999999
=10^12-2*10^6+1+19999999
=10^12-2*10^6+2*10^6
=10^12