The sum of the top and bottom of a trapezoid is 36dm, which is four times the height. The area of this trapezoid is______ dm2．

The sum of the top and bottom of a trapezoid is 36dm, which is four times the height. The area of this trapezoid is______ dm2．

The area of this trapezoid is 162 square decimeters. So the answer is: 162

What number divided by 8 equals 49 and has a remainder?

49*8=392
50*8=400
(392 + 1) / 8 = 49 + 1
.
(392 + 7) / 8 = 49 + 7
Between 393 and 399, the number divided by 8 equals 49, and there is a remainder

It is proved that the remainder of a complete square divided by 8 can only be 0, 1 and 4, and it is proved that a positive integer a, B and C satisfying the equation a ^ 2 + B ^ 2 = C ^ 2 must be a multiple of 4

All integers can be divided by the residue class of a number. For example, 9 can be divided into 9 residue classes: 9 - {0}, 9 - {1}, 9 - {2}, 9 - {3}, 9 - {4}, 9 - {5}, 9 - {6}

M square divided by 8, the remainder is 1
If M is odd, we can prove that the remainder of M squared divided by 8 is 1, but if M = 1, it is obviously not true

This is a proof problem: m is odd, then M is expressed as 2N-1, n = 1,2,3. To prove that the remainder of M squared divided by 8 is 1, just prove that m squared-1 can be divisible by 8. M squared-1 = (M + 1) (m-1) substitute M = 2N-1 into the above formula, and get: (2n-1 + 1) * (2n + 1 + 1) = 2n * (2n + 2) = 4N (n + 1) as long as 4N (...)

What does D in the arithmetic sequence formula an = a1 + (n-1) d mean?

If a sequence starts from the second term, and the difference between each term and its previous term is equal to the same constant, the sequence is called the arithmetic sequence, and the constant is called the tolerance of arithmetic sequence. The tolerance is usually expressed by the letter D

A sequence of numbers, the first term is 1, the second term is 4, each term is the sum of the products of the first two terms. Find the remainder of the 2004 term divided by 7

A1 = 1 = 4 ^ 0, A2 = 4 ^ 1, A3 = 4 ^ 1, A4 = 4 ^ 2,... Its exponents constitute Fibonacci sequence {FN} = {F0 = 0, F1 = 1, F2 = 1; 2,3,5,8,13,21,...} a (2004) = 4 ^ F2003. The meaning of the problem is to find 4 ^ F2003 mod 7

If there is a number greater than 100, the remainder of 5 is 2, and the remainder of 7 is 3. What is the minimum number?
Band arithmetic

Let n = 5A + 2 = 7b + 3
That is, a = (7b + 1) / 5 = B + (2B + 1) / 5
So 2B + 1 must be divided by 5, and 2b + 1 is odd, so 2B + 1 = 5 (2k + 1), B = 5K + 2,
So n = 7b + 3 = 7 (5K + 2) + 3 = 35K + 17
From n > 100, k > 2
Taking k = 3, the smallest n is n = 105 + 17 = 122

What is the remainder of the product of 28 × 541 × 1993 divided by 13
Make the formula clear

Use congruence
More than 2
541 ÷ 13 more than 8
More than 4
Therefore, the product of 28 × 541 × 1993 divided by the remainder of 13 is equivalent to the product of 2 × 8 × 4 divided by the remainder of 13
2×8×4 = 64
More than 12
Then the remainder of the product of 28 × 541 × 1993 divided by 13 is 12

What is the remainder of 15 × 38 × 412 × 541 △ 13? How to calculate it?
15 × 38 × 412 × 541 △ 13 remainder
=2 × 38 × 412 × 541 △ 13 remainder
=2 × 12 × 412 × 541 △ 13 remainder
=2 × 12 × 9 × 541 △ 13 remainder
=2 × 12 × 9 × 8 △ 13 remainder
=1728 △ 13 remainder
=12

15 × 38 × 412 × 541 △ 13 remainder
=2 × 38 × 412 × 541 △ 13 remainder
=2 × 12 × 412 × 541 △ 13 remainder
=2 × 12 × 9 × 541 △ 13 remainder
=2 × 12 × 9 × 8 △ 13 remainder
=1728 △ 13 remainder
=12

-What is the remainder of 193 divided by 13 - what is the remainder of 33 divided by 24
How to find the remainder when the negative number is divisor

-193÷13=-14…… eleven
-33÷24=-1…… nine
The multiplication and division of negative numbers meet the following requirements:
Division (or multiplication) of the same sign is positive and division (or multiplication) of different signs is negative