P is a point out of plane a. the angle difference between PA, Pb and plane a is π / 4. Their projective lengths in plane are 2 and 12 respectively. The distance from P to plane is
The larger the angle, the shorter the projection
Let the distance be d
tana=d/12,tan(a+π/4)=d/2
Because Tan (a + π / 4) = (1 + Tana) / (1-tana)
The solution is d = 4 or 6
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