PA, Pb and PC are three rays from P, and the angle between each two rays is 60 degrees. So what is the cosine of the angle between PC and PAB? Which is the angle between PC and PAB and why A proof of the angle between line PC and plane PAB

PA, Pb and PC are three rays from P, and the angle between each two rays is 60 degrees. So what is the cosine of the angle between PC and PAB? Which is the angle between PC and PAB and why A proof of the angle between line PC and plane PAB


This is a regular triangle with all angles of 60 degrees. Set the edge length to 2, and the height of the triangle is the root sign 3. The sine and cosine of the angle in the question are 2 / 2 root sign 3
Set a midpoint on the side of AB as D, then the angle cpd is the angle required in the title



PA, Pb and PC are three rays from P, and the angle between each two rays is 30 degrees. Then the cosine of the angle between PC and PAB is 0


In this paper, the length of PC pH (H point is the perpendicular foot from C point to AB in the triangle ABC) ch is calculated as PC = 1 / sin (15), pH = Tan (75) HC = Tan (60)