In terms of physical parameters, should the brightness of the two bulbs be compared by current, voltage or electric power?

In terms of physical parameters, should the brightness of the two bulbs be compared by current, voltage or electric power?

Electric power
It can be explained from two angles
1、 It can be considered that the higher the power, the higher the brightness. 2. If the energy conversion efficiency of the two bulbs is the same, the higher the electric power, the more light energy converted and the higher the brightness

Then the relationship between the voltage at both ends and the consumed electric power is as follows:
A. In series, the ratio of voltage is 1:2 and the ratio of electric power is 2:1
B. In series, the ratio of voltage is 2:1 and the ratio of electric power is 1:2
C. In parallel, the voltage ratio is 1:1 and the electric power ratio is 2:1
D. In parallel, the voltage ratio is 1:1 and the electric power ratio is 1:2
Don't be too detailed. Just teach me. What is the "voltage at both ends" only? Is it the total voltage?

The formula of electric power is p = u * I, so the ratio of electric power is equal to the ratio of voltage of each electric appliance. Because the current of the series circuit is equal everywhere, but the parallel circuit has no effect of voltage division, so the ratio of electric power is equal to the ratio of voltage of each electric appliance

Online and so on -- a junior high school physics problem (electric energy, electric power)
The following table is a part of the manual of a drying type automatic washing machine on the market. It is known that the washing time and dehydration time for the washing machine to complete a standard washing process are 20min and 10min respectively;
(1) How much electricity is consumed in the drying process?
(2) How long does it take to dry?
Attached (contents in the table)
Power supply: 220 V, 50 Hz
Washing power: 250W
Dehydration power: 300W
Heating power: 1650W
Washing capacity: 5kg
Rated water consumption: 79j
Maximum heating temperature: 95 ℃
Rated power consumption: 0.92kw · H
Overall dimension: 900mm * 400mm * 600mm

（1）W1=0.25KW×1/3h
W2=0.3KW × 1/6h
W = 0.92kwh-w1-w2
(2) T drying = w drying / 1.65kw

There is an automatic electric water bottle in the office. The principle and parameters are shown in the figure and table. A is the automatic temperature control switch. When the water temperature reaches the set temperature, the circuit will be automatically disconnected; when the water temperature is lower than the set temperature, the circuit will be automatically connected (1) 90% of the heat released by the electric water bottle is absorbed by the water. When a bottle of 20 ℃ water is boiled (standard atmospheric pressure), how long should the electric water bottle work normally? (2) When the yellow light is on, is the electric water bottle in the state of heat preservation or heating? What is the resistance of insulation element R when working? (the power consumed by indicator light can be ignored. Insulation power refers to the power consumed by the whole circuit) model p2l55-b power supply AC220V & nbsp; 50 Hz heating power 800W insulation Power 40W water capacity 2.0L

(1) M = ρ v = 1 × 103kg / m3 × 2 × 10-3m3 = 2kg; Q suction = cm (t1-t0) = 4.2 × 103J / (kg ·℃) × 2.0kg × (100 ℃ - 20 ℃) = 672000j; Q discharge = q suction ／ η = 672000j ／ 90% = 746666.7j; t = q discharge P = 746666.7j800w = 933.3s; (2) from the diagram, when the yellow light is on