Power loss of overhead transmission lines P = voltage squared / resistance P = current squared * resistance why in overhead transmission lines, power loss is often reduced by increasing voltage and reducing current, rather than by increasing current and reducing voltage?

Power loss of overhead transmission lines P = voltage squared / resistance P = current squared * resistance why in overhead transmission lines, power loss is often reduced by increasing voltage and reducing current, rather than by increasing current and reducing voltage?


If we reduce the voltage and increase the current, if we want to keep the transmission capacity unchanged, every time the voltage is reduced, the current will be doubled. According to the second formula you listed, the line loss will be increased by 3 times (4 times of the original). Obviously, it is not cost-effective



Why should China develop EHV transmission lines
The full text is written in English


I know,I know!
High-voltage transmission lines are used to transmit electric power over relatively long distances, usually from a central generating station to main substations.They are also used for electric power transmission from one central station to another for load sharing.High voltage (HV) transmission lines are made of high voltage (between 138 and 765 kilovolts) overhead and underground conducting lines of either copper or aluminum.
One of the key concerns in transmission of electricity is power loss in transmission lines (called line loss or transmission loss),dissipated as heat due to the resistance of the conductors.The smaller the surface area of the conductors,the smaller the loss to heat dissipation.High voltages require less surface area, resulting in reduced line loss.With high-voltage lines,the voltage can be stepped up at the generating station,transmitted through the transmission grid to a load center,and there stepped down to the lower voltages required by distribution lines.



Reducing the active power loss of transmission line can be achieved by
A. Increase the line active power B, increase the line reactive power
C. Increase the voltage d at both ends of the line and increase the resistance of the transmission line


C. Increase the voltage at both ends of the line



n> N0, which master can explain how the three-phase asynchronous motor generates power when the rotor speed is greater than the rotating magnetic field speed


If the output end of the motor is connected with a capacitor, the weak electric energy can act on the capacitor to charge and discharge, which can provide the excitation of the rotor magnetic energy to enhance, and the winding can induce a slightly larger electromotive force, which can act on the capacitor to charge and discharge, which can provide the excitation of the rotor magnetic energy to further enhance, You can generate enough power