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A. The distance between B and a is 20 kilometers. A and B walk from a to B. A walks 4 kilometers per hour. B rides a bicycle at 2.5 times the speed of A. a walks for an hour first, and B sets out. When B catches up with a, he immediately returns to a, then returns to a, and when B catches up with a, he immediately returns to a, and then returns to a, How many kilometers did B walk?
The time for a to walk is 20 / 4 = 5 hours
The time for B to walk is 5-1 = 4 hours
The distance of B is 4 * 2.5 * 4 = 40 km
A B walked 40 kilometers,
A. The distance between two places B is 20 kilometers. A and B set out from a and B at the same time and face each other. The speed is 5.5 km / h and 4.5 km / h respectively. Now a and a dog set out with them
The speed of the dog is 12km / h. When the dog meets with B, it starts to run back and forth between a and B. regardless of the time required for the dog to turn, how much distance does the dog run when a and B meet?
Let a and B take t hours from departure to meeting
t = 20 / (5.5 + 4.5)
=2 hours
The distance a dog runs is s,
s = 12t
=24 km
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