AB is 100km away, a is 20km / h in place a, B is 30km / h in place B, a starts one hour later, B starts two people contrary to each other, B starts several hours, two people are 200km away

(200-100-20*1)/(20+30)=1.6

The distance between a and B is 500km, a 20km / h and B 30km / h. The two vehicles start from AB and go in the same direction. A is in the front and B is in the back. How many hours later does B catch up with a?

Let B catch up with a in X hours
30x-20x=500
10x=500
x=50
So 50 hours later, B overtakes a

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