The walking speed ratio of a and B is 13:11. They start from a and B at the same time and walk in opposite directions. They meet half an hour later. It's like walking in opposite directions. How small does it take for a to catch up with B

The walking speed ratio of a and B is 13:11. They start from a and B at the same time and walk in opposite directions. They meet half an hour later. It's like walking in opposite directions. How small does it take for a to catch up with B

Suppose the speed of two people is 13 and 11 respectively
When traveling in opposite directions, the total speed is 13 + 11 = 24, so the distance between the two places is 24 * 0.5 = 12
When traveling in the same direction, the time for a to catch up with B, that is, the time for a to travel the distance between two places
The speed difference is 13-11 = 2, so the time is: 12 / 2 = 6 hours
Comprehensive formula: (13 + 11) * 0.5 / (13-11) = 6 hours
A: it takes six hours for a to catch up with B

The walking speed ratio of a and B is 13:11. They walk from AB to ab at the same time and meet each other in 0.5 hours. If they walk in the same direction, how many hours will it take a to catch up with B?
What is this question about?
If we go in the same direction and start at the same time, how can we still have the problem of who can catch up with whom?
Which Idiot's problem is this? I don't understand
This topic is a bit confused. The author didn't express his problem clearly. In order to understand his meaning, the problem solver needs to help him improve the whole problem.

First of all, the first half of the title gives the meaning that there is a distance between AB, that is, the distance between a and B is certain. The idea of the title is: 1. To find the distance between the two places, let a's speed be 13V, B's speed be 11V, then the distance between AB and ab is: (13V + 11V) × 0.5 = 12V2

A and B cars are running opposite each other from AB, and a car starts 15 minutes earlier than B car. The speed ratio of a and B cars is 2:3, when they meet,
Car a is 6 kilometers less than car B. It's known that car B takes 1.5 hours to walk this road. Please find the speed of car a and the distance between car a and car B

A speed of 2x, B 3x
The distance is 3x * 1.5
Let a walk y + 0.25 hours and B walk y hours
2X*(Y+0.25)+6=3XY
3XY+2X*(Y+0.25)=3X*1.5
The solution is x = 20, y = 0.8
Then speed a is 40 and speed B is 60
When meeting, a walked for 1.05 hours, B walked for 0.8 hours

A and B two cars from AB two opposite, a car than B car started 15 minutes earlier, B car speed is one and a half times the speed of a car, meet a car less than B
Walk 6 pinch noodles. The speed of a car is 10 meters per hour. Find the distance between two places

The speed of car a is 10km per hour, and that of car B is 1.5 * 10 = 15km,
If the driving time of vehicle a is t hours, the driving time of vehicle B is T-1 / 4
The solution of the equation 10t + 6 = 15 (t-1 / 4) is t = 1.95
The distance between a and B is 10t + 15 (t-1 / 4) = 22.05km