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Party A and Party B set out at the same time from AB, which is 120 kilometers away, and they were walking towards each other. Party A rode 18 kilometers per hour, and Party B walked for five hours before they met, Solve by equation
Suppose B X
5X+5*18=120
5X=120-90
5X=30
X=6
A: B: 6 kilometers per hour
The walking speed ratio of a and B is 13:11. If a and B start from a and B at the same time and walk in opposite directions, they will meet in 0.5 hours. If they walk in the same direction, it will take () hours for a to catch up with B
A. 4.5B. 5C. 5.5D. 6
Suppose that the speed of a is 13 kilometers per hour, and that of B is 11 kilometers per hour. According to the meaning of the question, the distance between the two places is: (13 + 11) × 0.5 = 24 × 0.5 = 12 (kilometers) and a needs to catch up with B: 12 △ 13-11 = 12 △ 2 = 6 (hours)
The walking speed ratio of Party A and Party B is 13:11. If Party A and Party B start from a and B at the same time and walk in opposite directions, they will meet in 0.5 hours. How long will it take if they walk in the same direction
Why did you catch up
(13 + 11) × 0.5 ÷ (13-11) = 3.5 hours
(13 + 11) × 0.5, calculate the total distance between the two places. (13-11) speed difference. (13 + 11) × 0.5 ÷ (13-11) = 3.5 hours
The distance between the two places is in the same direction, and the distance difference is divided by the speed difference to find out the time of meeting!
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