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A and B are facing each other. A leaves 15 minutes earlier than B. the speed ratio of the two cars is 2; 3. When they meet, a walks 6 kilometers less than B. It is known that B walks for 1 hour and 30 minutes It is known that Party B walked for 1 hour and 30 minutes to find out the speed of the two cars and the distance between them
If the speed of car a is x km / h, the speed of car B is 1.5 x km / h
x(0.25+1.5)=1.5x*1.5-6
The solution is: x = 12. The speed of car B is 1.5x = 18
The distance between the two places is 12 (0.25 + 1.5) + 1.5 * 12 * 1.5 = 48
A: the speed of a and B is 12 km / h and 18 km / h respectively, and the distance between the two places is 48 km
Party A and Party B go from place a to place B. Party A walks for 2 hours before Party B starts. As a result, Party B is 15 minutes late than Party A. the speed of Party A is 5 kilometers, and the speed of Party B is 5 kilometers
Party A and Party B go from place a to place B. Party A walks for 2 hours before Party B starts. As a result, Party B is 15 minutes late than Party A. the speed of Party A is 5 km / h, and the speed of Party B is 8 km / h. find the distance between two places (linear equation with one variable)
If the distance between the two places is set at x km, the following results can be obtained:
x/5 -2=x/8+1/4
8x-80=5x+10
3x=90
x=30
A and B went from a to B. A walked for 2 hours before B started. As a result, B arrived 20 minutes earlier than a, and the speed was 4 km / h
B's speed is 6km / h, find the distance between two places of AB, and let X be the distance
Let the distance between the two places be X
X/6=X/4-2-20/60
2+1/3=X/4-X/6
7/3=X/12
X=28km
The fast and slow trains leave from a and B at the same time. The fast train runs 80 kilometers per hour, 10 kilometers faster than the slow train. After 4 hours
The fast and slow trains leave from a and B at the same time. The fast train runs 80 kilometers per hour, 10 kilometers faster than the slow train. Four hours later, the two trains are still one fourth of the distance. If on a map with a scale of 1:4000000, how many centimeters is the distance between a and B?
The speed of the local train is 80-10 = 70 km / h
The 4-hour two car journey is 4 × (80 + 70) = 600 km
The whole journey is 600 (1-1 / 4) = 800 km
800km = 80000000cm
The distance between a and B is 80000000 × 1 / 4000000 = 20cm
A: the distance between a and B is 20cm
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