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Party A and Party B set out from a and B at the same time and walked in opposite directions. Three hours later, they met on the way. It is known that a and B are 24 kilometers apart, and the speed ratio of Party A and Party B is 2:3 Ask a and B how many kilometers per hour
Two person speed sum = 24 △ 3 = 8 km / h
Therefore, a travels 8 △ (2 + 3) × 2 = 3.2km per hour
B: 8-3.2 = 4.8km per hour
Car a and car B drive from station a to station B at the speed of 48 km / h and 70 km / h respectively. Car a walks for one hour before car B starts. How many hours can car B catch up with car a?
Car a walked for one hour and 48 kilometers first, and car B caught up with car a in three minutes
48 ÷ (70-48) ≈ 2.18 (hours)
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The distance s between the train and a station is expressed as a function of time t by analytic formula after the train has driven for 50 minutes at the speed of 60 km / h after 5 km from a station
S=5+60t(0≤t≤5/6）
A train starts from a certain station at the speed of 48 kilometers per hour, and then leaves a bus from the same station in the same direction 50 minutes later. It is known that the speed of the bus is one and one sixth of that of the train. How long does it take for the train to catch up with the train?
The distance between bus and coach is s = V, t = 48km / h * 5 / 6h = 40km
The speed of the bus relative to the train v = (7 / 6-1) v = 8km / h
The time for the bus to catch up with the train is 40km / (8km / h) = 5h
That is to say, the bus can catch up with the train only after the train runs for another 5 hours
RELATED INFORMATIONS
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