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A. B: the distance between the two places is 240 km. It takes 4 hours for the train to run at the original speed. After the train speed is increased, the speed is 30% faster than the original speed, so only () A. 3310 hours B. 3113 hours C. 4310 hours D. 4113 hours
A. B is 240 km away from the two places. If the train runs at the original speed for 4 hours, then the original speed is 240 △ 4 = 60 km / h. If the speed is 30% faster than the original speed, then the speed will be 60 × (1 + 30%) = 78 km / H. if the speed is increased, then it will only take 240 △ 78 = 3113 hours
The distance between stations AB and ab is s km. The passenger and freight trains need to travel at the speed of Y km / h respectively
How many hours have you been driving at 24 km [before the two cars meet]?
S-24/x+y
A. B: the distance between the two places is 240 km. It takes 4 hours for the train to run at the original speed. After the train speed is increased, the speed is 30% faster than the original speed, so only ()
A. 3310 hours B. 3113 hours C. 4310 hours D. 4113 hours
A. B is 240 km away from the two places. If the train runs at the original speed for 4 hours, then the original speed is 240 △ 4 = 60 km / h. If the speed is 30% faster than the original speed, then the speed will be 60 × (1 + 30%) = 78 km / H. if the speed is increased, then it will only take 240 △ 78 = 3113 hours
A train departs from a to B at 8:00 a.m., 180 kilometers away from a at 10:00 a.m., 540 kilometers away from a and B. how many hours does it take to complete the whole journey?
10-8 = 2 (hours), 540 ^ [(540-180) ^ 2], = 540 ^ [360 ^ 2], = 540 ^ 180, = 3 (hours); a: it takes 3 hours to complete the whole journey
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