The two trains leave from ab at the same time. A travels 50 kilometers per hour. B travels 80% of a's speed. Every hour, the distance between the two trains is shorter Shorten the whole process by one ninth, and seek the whole process

The two trains leave from ab at the same time. A travels 50 kilometers per hour. B travels 80% of a's speed. Every hour, the distance between the two trains is shorter Shorten the whole process by one ninth, and seek the whole process

50 × 80% = 40 km
(50 + 40) △ 1 / 9 = 810km
Answer: the whole journey is 810km

On a map with a line scale of 0 -- 60 -- 120 km, the distance between AB and ab is 12. A train runs from a to B at a speed of 80 km per hour
How long does it take for the train to travel

The solution is as follows
(1) Let AB be x kilometers away
1:60==12:x
X = = 720 (km)
(2) The train time from a to B is:
720 / 80 = = 9 (hours)

If the speed of a train from a to B is increased by 20%, it can arrive one hour earlier than the specified time. The original speed of the train is 165km / h
If the speed of a train from a to B is increased by 20%, it can arrive one hour earlier than the specified time. The original speed of the train is 165 kilometers per hour, and the distance between two places can be calculated

Let AB be x km,
Then (x / 165) - X / 165 × (1 + 20%) = 1
The solution is x = 990

A train goes from city a to city B, which is 240 kilometers away. After driving for 5 minutes and 2 hours, it is 40 kilometers away from the midpoint. At this speed, the train arrives
How long does it take for this train to reach city B?

1. Possible: 240 △ 2 / 5
=240÷200
=1.2 hours
2、240÷[(240÷2+40)÷2/5]
=240÷400
=0.6 hours