A and B leave from ab at the same time. Car a runs 50 kilometers per hour. Car B's speed is 4 / 5 of car a's. after meeting, car a goes on for 2.4 kilometers How many kilometers is the distance between a and B

A and B leave from ab at the same time. Car a runs 50 kilometers per hour. Car B's speed is 4 / 5 of car a's. after meeting, car a goes on for 2.4 kilometers How many kilometers is the distance between a and B


2.4 × 50 = 120 km
1÷(1+4/5)=5/9
1-5/9=4/9
120 △ 4 / 9 = 270 km
A: the distance between the two places is 270 km



A and B leave from a and B at the same time. A travels 50 kilometers per hour. B's speed is 4 / 5 of a's. after meeting, a goes on
2.4 hours to B, how many kilometers are there between a and B?
(please feel sorry for me ~ ~ our teacher still needs to draw a picture. Please do me a favor and draw a picture as you solve it.)


Speed of B: 50 × 4 / 5 = 40 kmh
The distance a continues to drive: 50 × 2.4 = 120 km
Time for meeting: 120 △ 40 = 3 hours
A. B distance between the two places: (50 + 40) × 3 = 90 × 3 = 270 km



A and B leave from ab at the same time. A travels 50km per hour. B's speed is after a 5 / 4 meeting. A continues to travel 2.4 hours to B. how many meters is the distance between AB and a
A and B are opposite each other from ab at the same time. When they leave a, they travel 50km per hour. B's speed is 5 / 4 of a's. after they meet, they continue to travel 2.4 hours to reach B. how many kilometers are there between AB and a?


B's speed is: 50 × 5 / 4 = 62.5, the speed ratio of the two cars is: 50:62.5 = 1:1.25, the time is fixed, the speed ratio is the distance ratio, when they meet, they walk 1:1.25, 1.25 takes 2.4 hours, 1 distance takes 2.4 × 1 / 1.25 = 1.92 (hours), the total time is 1.92 + 2.4 = 4.32ab, the distance between the two places is



A and B leave from a and B at the same time and meet each other in two hours. After meeting, the two vehicles continue to move forward. When a arrives at B, B is 60 kilometers away from A. the speed ratio of the two vehicles is known to be 3:2?


If the whole process is regarded as unit "1", then the distance between a and B is 60 (1-12 × 43) = 60 / 13, = 180 (km). The speed sum of a and B is 180 / 2 = 90 (km)