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The distance between the two places is 480 km. The two vehicles leave each other at the same time and meet in 3 hours. The speed ratio of the two vehicles is 9:7 How many kilometers did a walk? (answer as soon as possible)
480/(9+7)*9=270
Two cars a and B leave 324km away from each other at the same time and meet on the way three hours later. It is known that the speed of car a is four fifths of that of car B
It's today,
1. Speed sum of a and B = 324 △ 3 = 108 km / h
The speed of car a is four fifths of that of car B, that is, the speed ratio of car a to car B is 4 ∶ 5
The speed of a accounted for 4 / 9 of the total, and the speed of B accounted for 5 / 9
Speed of B = 108 × 5 / 9 = 60 km / h
Synthesis formula
（324÷3）÷（1+4/5）
=108×5/9
=60 km / h
2. Let B's speed be x km / h
3(4/5x+x)=324
x=60
The distance between a and B is 480 kilometers. AB and ab are going to meet each other in 6 hours. We know that the speed ratio of AB and ab is 9:7. What's the speed ratio of AB and ab?
480÷6=80
80÷（9+7)=5
Car a speed 5 × 9 = 45
B two car speed 5 × 7 = 35
The distance between a and B is 480km. Two cars a and B start from two places at the same time and run in opposite directions. They meet in six hours. The speed of a and B is known
The ratio is 9:7. What is the speed of a and B?
Speed sum: 480 △ 6 = 80 (km / h)
Speed of car a: 80 ÷ (9 + 7) x9 = 45 (km / h)
Speed of car B: 80-45 = 35 (km / h))
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