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The distance between the two places is 30km. The speed of a is 6km / h and that of B is 4km / h The two are going in opposite directions, and the distance between them is 40km after a few hours
40km apart
40 - 30 = 10km, that is, they walked 10km
T = 10 (4 + 6) = 1 hour
One hour, a few hours later, the distance is 40km
The speed of a is 4km, the speed of B is 6km, the sum of three consecutive odd numbers is 45
Three numbers?
All are solved by equations
B and AB, 20km apart, are traveling at the same time. A's speed is 4km. B's speed is 6km. How many hours will they meet
Let's meet in X hours
（4+6）x=20
10x=20
x=2
The sum of three consecutive odd numbers is 45?
Let the middle number be X
x-2+x+x+2=45
3x=45
x=15
x-2=13
x+2=17
These three numbers are 13, 15 and 17
The distance between a and B is 600 km. The two trains run from each other. If they start at the same time, they will meet in 6 hours. If B starts 5 hours first, they will meet in 3 hours
The topic is not complete, add as follows: find a and B two car speed
If the speeds of vehicle a and vehicle B are V1 and V2 respectively
V1+V2=600/6=100 （1）
3V1+8V2=600 （2）
Formula 2-1 * 3:5v2 = 300, V2 = 60. Substitute Formula 1: V1 = 40
The speed of vehicle a is 40km / h, and that of vehicle B is 60km / h
The distance between AB and a is 500km. The two cars run from AB to B. if they start at the same time, they will meet each other 5h. If B starts 5h earlier, they will meet each other 3H
Find the speed of a and B cars
Set a x km / h, set b y km / h
(x+y)*5=500,x+y=100,x=100-y
x*3+y*(5+3)=500,3x+8y=500
3(100-y)+8y=500
300-3y+8y=500
5y=200
y=40,
x=60
A: a 60 km / h, B 40 km / h
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