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The two trains of a and B run from two places 600 kilometers apart at the same time. Two and a half hours later, the two trains are 220 kilometers apart?
Let car B travel x kilometers per hour. According to the meaning of the question, 80 × 2.5 + 2.5x + 220 = 600, & nbsp; & nbsp; & nbsp; 200 + 2.5x + 220 = 600, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2.5x + 420 = 600, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp
The two trains of Party A and Party B travel at the same time from two places 600 km apart. Four hours later, the two trains are 200 km apart. It is known that the train of Party A travels 80? A per hour
Formula
600-200 = 400km 400 / 4 = 100km B speed 100-80 = 20km / h
The two trains leave from 1313km apart at the same time. After 3 hours, they are 707km apart. After a few hours, they meet. Why
The main reason is why it can not be used and why. I don't understand this topic
(1313-707) △ 3 = 202 km
Then the sum of the two vehicle speeds is 202 km / h
707 △ 202 = 3.5 hours
A: after another 3.5 hours, the two cars meet
At the same time, the two trains depart from the two places 1313km apart, 707km apart in three hours, and 707km apart in a few hours?
Speed sum = (1313-707) △ 3 = 202 km / h
After = (707 + 707) △ 202 = 7 hours
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