Beside the railway line, there is a highway along the direction of the railway. On the highway, a car is driving at the speed of 45 kilometers per hour. At this time, a train is coming from behind at the speed of 63 kilometers per hour. It takes 56 seconds for the train to pass by the car from the front to the rear. How many meters is the total length of the train? (excluding the length of the car)

Beside the railway line, there is a highway along the direction of the railway. On the highway, a car is driving at the speed of 45 kilometers per hour. At this time, a train is coming from behind at the speed of 63 kilometers per hour. It takes 56 seconds for the train to pass by the car from the front to the rear. How many meters is the total length of the train? (excluding the length of the car)

Two cars one hour fast 63-45 = 18km = 18000m
Turn into seconds is fast per second: 18000 △ 3600 = 5m
Total length: 56x5 = 280m

One car goes from place a to place B at a speed of 45 km / h, and the other car goes from place B to place a at a speed of 50 km / h. The distance between a and B is 140 km. How far is it from place B where the two cars meet? (first use arithmetic solution, then use equation solution)
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The arithmetic solution is: after one hour, the distance between two vehicles is 140-45 = 95km, the meeting time of two vehicles is 95 / (45 + 50) = 1H, the distance between the meeting ground and B is 50 * 1 = 50km, the equation solution is: let the distance between the meeting ground and B be s (140-45-s) / 45 = s / 50, the solution is s = 50, or let the meeting time be x (145-45) = (45 = 50) * x, the solution is x = 1