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A passenger car and a freight car run from Party A and Party B at the same time. After 6 hours, they meet. The passenger car runs 60 km per hour, and the freight car 15 is the distance between Party A and Party B How many meters?
If the freight car completes the whole journey in 15 hours, it will travel 6 / 15 of the whole journey in 6 hours, and the passenger car will travel 1-6 / 15 = 9 / 15 = 3 / 5 of the whole journey
The distance between the two places
6×60÷（1-6×1/15）
=360÷3/5
=360×5/3
=600（km）
A freight car and a passenger car are going from place a to place B at the same time. The freight car travels 60 kilometers per hour, and the passenger car 65 kilometers per hour. When the passenger car arrives at city B, the freight car has to travel more
How far is the distance between a and B?
60 × 0.5 ÷ (65-50) × 65 = 390km
A bus goes from city a to city B, traveling 60 kilometers per hour. After 2 o'clock, a truck runs from city B to city a, and meets the bus after 4 o'clock. At this time, the truck runs one third of the whole journey. How many kilometers are there between the two cities?
most urgent!
If the speed of the freight car is a km / h, then
4*（60+a）+60*2=3*（4a）
The solution is a = 45
So the distance between the two cities = 3 * (4 * 45) = 540km
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