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It takes 10 hours for a bus to go from place a to place B, and 15 hours for a truck to go from place B to place a. the two cars set out at the same time, and the distance between them is 25000 when they meet
The time ratio of bus to truck is 10 ∶ 15 = 2 ∶ 3,
If the distance is equal, the speed is inversely proportional to the time,
It can be concluded that the speed ratio of passenger cars to freight cars is 3 ∶ 2,
When they meet, the bus takes 3 / (3 + 2) = 3 / 5 of the whole journey,
It can be concluded that the distance between a and B is 25 ^ (3 / 5-1 / 2) = 250 km
It takes 10 hours for a freight car to go from place a to place B, and 5 hours for a passenger car. The two cars are facing each other at the same time. When they meet, the passenger car travels 90km more than the freight car. What's the distance between the two places?
Freight cars travel 1 / 10 per hour and passenger cars 1 / 5 per hour
Meeting time: 1 △ 1 / 10 + 1 / 5 = 10 / 3 (hours)
1 / 10 × 10 / 3 = 1 / 3
The bus line: 1 / 5 × 10 / 3 = 2 / 3
Passenger cars travel more than freight cars: 2 / 3-1 / 3 = 1 / 3
Whole course: 90 △ 1 / 3 = 270 (km)
A passenger car and a freight car run from both sides at the same time. The freight car runs 60km per hour and the passenger car 52km per hour,
16 ÷ (1 / 52-1 / 60) = 16 ÷ 2 / 390 = 3120km
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