In the first semester of the first semester of junior high school, we can use equation or not, but there must be process A and B ride bicycles on the road parallel to the railway. They ride 15 kilometers per hour. Now there is a train coming. It takes 30 seconds for the train to pass by a and 20 seconds for the train to pass by B. the speed of the train is calculated
The mathematical method is simple. Let the train length be x and the train speed be y
X / (Y-15) = 30 and X / (y + 15) = 20
The result is y = 75, which is what you want
A and B bicycles, on the road parallel to the railway, travel 15 kilometers per hour. There is a train coming. It takes 30 seconds for the train to pass a bicycle and 20 seconds for the train to pass B bicycle. The speed of the train is calculated
15 km / h = 416 M / s. assuming the train speed is x m / s, the equation can be obtained as follows: (416 + x) × 20 = (x-416) × 30 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 8313x + 20x = 30x-125, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 10x = 20813, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 2056. A: the train speed is 2056 M / s
A and B bicycles, on the road parallel to the railway, travel 15 kilometers per hour. There is a train coming. It takes 30 seconds for the train to pass a bicycle and 20 seconds for the train to pass B bicycle. The speed of the train is calculated
15 km / h = 416 M / s, assuming that the speed of the train is x m / s, the equation can be obtained as follows: (416 + x) × 20 = (x-416) × 30 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 8313x + 20x = 30x-125, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 10x = 20813, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp