"Everyone has the right to live, and everyone can create a colorful world of their own." The meaning of a sentence

"Everyone has the right to live, and everyone can create a colorful world of their own." The meaning of a sentence

No one is allowed to infringe upon citizens' rights. Citizens have the right to exercise their own rights and exclude infringement by others

Everyone has the right to live, who can create a colorful world of their own?

What kind of life you want, you have the right to choose, and your life depends on your own hands to create. The life you create for yourself is colorful, maybe it doesn't have much material and fame

Everyone has the right to live, who can create a colorful world of their own

Isn't the literal meaning obvious? It doesn't mean much, does it?

There is a rope hanging on the car at two points ab. there is a piece of material on the rope with a mass of M. when the car is at rest, the rope is suspended AC.BC When the angle is 53 degrees and 37 degrees respectively, then
【1】 When the car moves to the right with an acceleration of a = 0.5g, calculate the tension of AC rope
【2】 When the car moves to the right with the acceleration of a = 2, find the pull of BC rope

First, find the critical value: when the tension of one of the ropes is exactly zero, the acceleration of the object is zero
A = g * Tan θ A1 = 0.75, A2 = 4 / 3, so when the acceleration is 0.5, two ropes have tensile force, when the acceleration is 2, only one rope has tensile force!

For example, cos. 37 = 0. 8, sin37 = 0. 6 or something, I want some common ones

cos0=1,sin0=0;
cos30=0.866,sin30=0.5;
cos37=0.8,sin37=0.6;
cos45=0.707;sin45=0.707;
cos53=0.6;sin53=0.8;
cos60=0.5;sin60=0.866;
cos90=0,sin90=1.

What are the sizes of cos37 sin37 tan37 cos53 cos53 tan53

Ha ha, are you doing the balance of force? Remember: cos37 ° = 4 / 5sin37 ° = 3 / 5 = cos53 ° tan37 ° = 3 / 4tan53 ° = 4 / 3. Note that these results are not accurate. As for how to get them, you just need to remember

How to decompose sin α sin β + cos α cos β
Sin α sin β + cos α cos β seems to be equal to SOC (α - β),
Master give me a step, thank you

In the form of asin α cos β + bcos α sin β, we can extract the root sign (a + b) and then we can use the formula
For example, sin α sin β + cos α cos β can first change the function name and extract (1 + 1) under the root sign, that is, root sign 2
Then you can

How to judge when to use sin, when to use COS and when to use Tan when to do the decomposition of force

When the resultant force is known, sin α is used for the vertical component and cos α is used for the horizontal component; when the horizontal component is known, vertical component = horizontal component * Tan α

Properties and usage of sin cos Tan
The more detailed the better, I didn't listen to you before. I know, please~

In a right triangle
Sin @ stands for the opposite side to the bevel side
Cos @ denotes that the adjacent edge is larger than the hypotenuse
Tan @ stands for the opposite side to the adjacent side
Cot @ stands for adjacent edge to edge
Basic relations of trigonometric functions with the same angle
Reciprocal relation: quotient relation: square relation:
tanα ·cotα＝1
sinα ·cscα＝1
cosα ·secα＝1 sinα/cosα＝tanα＝secα/cscα
cosα/sinα＝cotα＝cscα/secα sin2α＋cos2α＝1
1＋tan2α＝sec2α
1＋cot2α＝csc2α
Induction formula
sin（－α）＝－sinα
cos（－α）＝cosα tan（－α）＝－tanα
cot（－α）＝－cotα
sin（π/2－α）＝cosα
cos（π/2－α）＝sinα
tan（π/2－α）＝cotα
cot（π/2－α）＝tanα
sin（π/2＋α）＝cosα
cos（π/2＋α）＝－sinα
tan（π/2＋α）＝－cotα
cot（π/2＋α）＝－tanα
sin（π－α）＝sinα
cos（π－α）＝－cosα
tan（π－α）＝－tanα
cot（π－α）＝－cotα
sin（π＋α）＝－sinα
cos（π＋α）＝－cosα
tan（π＋α）＝tanα
cot（π＋α）＝cotα
sin（3π/2－α）＝－cosα
cos（3π/2－α）＝－sinα
tan（3π/2－α）＝cotα
cot（3π/2－α）＝tanα
sin（3π/2＋α）＝－cosα
cos（3π/2＋α）＝sinα
tan（3π/2＋α）＝－cotα
cot（3π/2＋α）＝－tanα
sin（2π－α）＝－sinα
cos（2π－α）＝cosα
tan（2π－α）＝－tanα
cot（2π－α）＝－cotα
sin（2kπ＋α）＝sinα
cos（2kπ＋α）＝cosα
tan（2kπ＋α）＝tanα
cot（2kπ＋α）＝cotα
(where k ∈ z)
Trigonometric function formula and universal formula of sum and difference of two angles
sin（α＋β）＝sinαcosβ＋cosαsinβ
sin（α－β）＝sinαcosβ－cosαsinβ
cos（α＋β）＝cosαcosβ－sinαsinβ
cos（α－β）＝cosαcosβ＋sinαsinβ
tanα＋tanβ
tan（α＋β）＝——————
1－tanα ·tanβ
tanα－tanβ
tan（α－β）＝——————
1＋tanα ·tanβ
2tan(α/2)
sinα＝——————
1＋tan2(α/2)
1－tan2(α/2)
cosα＝——————
1＋tan2(α/2)
2tan(α/2)
tanα＝——————
1－tan2(α/2)
Sine, cosine and tangent formulas of half angle
The formula of sine, cosine and tangent of double angle the formula of sine, cosine and tangent of triple angle
sin2α＝2sinαcosα
cos2α＝cos2α－sin2α＝2cos2α－1＝1－2sin2α
2tanα
tan2α＝—————
1－tan2α
sin3α＝3sinα－4sin3α
cos3α＝4cos3α－3cosα
3tanα－tan3α
tan3α＝——————
1－3tan2α
Sum difference product formula of trigonometric function
α＋β α－β
sinα＋sinβ＝2sin—－－·cos—－—
2 2
α＋β α－β
sinα－sinβ＝2cos—－－·sin—－—
2 2
α＋β α－β
cosα＋cosβ＝2cos—－－·cos—－—
2 2
α＋β α－β
cosα－cosβ＝－2sin—－－·sin—－—
2 2 1
sinα ·cosβ＝-[sin（α＋β）＋sin（α－β）]
two
one
cosα ·sinβ＝-[sin（α＋β）－sin（α－β）]
two
one
cosα ·cosβ＝-[cos（α＋β）＋cos（α－β）]
two
one
sinα ·sinβ＝－ -[cos（α＋β）－cos（α－β）]
two
The form of trigonometric function for transforming asin α ± bcos α into an angle (the formula of trigonometric function of auxiliary angle)

When to use cos, when to use sin, and when to use tan?

Given the resultant force F and its angle, cos is used to calculate the horizontal component force F1,
Let's know F1 and its included angle and find the force of the included angle pair F2 with sin,
If we know F1 and its angle, we can find another component F2 with tan,