How to calculate all prime numbers within 100

How to calculate all prime numbers within 100

If it is a program # include # include int isprime (int x); int main() {int i; for (I = 2; I

What are all prime numbers within 100?
If you want all the prime numbers within 100, you have to follow a larger order. Please tell me that all the prime numbers within 100 can't be more or less,

2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97

Let's find all prime numbers within 100
Must be in order, and to type out a word!
Wrong press, it's less than 1000!

2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 2...

Like 1 / 2, 1 / 3, 1 / 4, 1 / 5 In this way, the fraction whose numerator is 1 and denominator is a natural number (except 0 and 1) is called unit fraction
Can you use the sum of the fractions in two different units to represent the following fractions?
5/6=1/?+1/? 7/10=1/?+1/? 10/21=1/?+1/? 1/6=1/?+1/?

5/6=1/2+1/3
7/10=1/2+1/5
10/21=1/3+1/7
1/6=1/42+1/7
The answer is not unique

The numerator and denominator of a true fraction are two continuous natural numbers. If the denominator is divided into 2 out of 3 after adding 4, what is the original fraction?

Let the original fraction be x / y
x/（y+4）=2/3 x+1=y x= 10 y= 11
The original score was 10 / 11

The sum of three consecutive even numbers is 120. What are the three even numbers?

Let the smallest one of the three consecutive even numbers with sum 120 be x, and the equation: x + X + 2 + X + 4 = 120 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 3x + 6 = 120 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 3x = 114 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 38, then x + 2 = 38 + 2

In 2002, the product of days, years, months and days is exactly equal to 120120

120120 / 2002 = 60 = 2 * 2 * 3 * 5, so March 20, April 15, May 12, June 10, October 6, December 5, a total of 6 days

Which days, years, divisors and days of 2002 exactly equal to 120120?

120120/2002=60
That is, there is a month * day = 60
60=1*60=2*30=3*20=4*15=5*12=6*10
So, according to 1

In which days of 2000, the product of the number of years, months and dates is exactly equal to the product of three consecutive multiples of 5 (such as 5, 10 and 15)?

The characteristics of the multiple of the product of three consecutive 5 are: 125 × X; the product of year, month and day is; 2000 × months × dates; so 125 × x = 2000 × months × dates, then 2000 ／ 125 = 16, so x must be a multiple of 16 and obtained by multiplying three consecutive integers, so the conditions are: (1) 6 × 7 × 8 = 336336 ／ 16 = 21, 3 × 7 = 21, 1 × 21 = 21, so there are March 7, 2000 and July 3, 2000 (2) 8 × 9 × 10 = 720, 720 △ 16 = 45, 3 × 15 = 45 5 × 9 = 45, so March 15, 2000, May 9, 2000, September 5, 2000; (3) 14 × 15 × 16 = 33603360 △ 16 = 210, 7 × 30 = 210, 10 × 21 = 210. So July 30, 2000, October 21, 2000; a: may be March 7, 2000, July 3, 2000, January 21, 2000, March 15, 2000, May 9, 2000, September 5, 2000, July 30, 2000, October 21, 2000

On a certain day in 1984, the product of the three numbers is exactly equal to the product of three continuous natural numbers. Which month and which day is this?

March 5
May 3rd