Answer to 100 exercises of solving equations in grade five

(0.5+x)+x=9.8÷2 2(X+X+0.5)=9.8 25000+x=6x 3200=450+5X+X X-0.8X=6 12x-8x=4.8 7.5*2X=15 1.2x=81.6 x+5.6=9.4 x-0.7x=3.6 91÷x ＝1.3 X+8.3=10.7 15x ＝3 3x－8＝16 7(x-2)=2x+3 3x+9=2718(x-2)...

Ask a question about the approximate score and the general score?
Excuse me, under what premise do you want to make score reduction or general score? And how do you make score reduction or general score? (please give an example)

Reduction is for the numerator and denominator of fractions. If the numerator and denominator have the same common divisor, that is not the simplest fraction, the numerator and denominator can be divided by an integer at the same time and finally get an integer. For example, 12 / 15, 12 and 15 have a common divisor 3, 12 divided by 3 gets 4, 15 divided by 3 gets 5, so it can be reduced, that is, 12 / 15 divided by 3 at the same time to get 4 / 5
General score is used in addition and subtraction of fractions, that is, if two fractions with different denominators want to do addition and subtraction, the numerators can only be added when the denominators are the same, for example, 3 / 4 + 4 / 5. At this time, they can't add directly. They should divide the denominators, that is, the denominators of two fractions are 4 times 5 and 20, that is, 15 / 20 + 16 / 20 = 31 / 20

General score and approximate score do not change the size of the score______ (judge right or wrong)

According to the basic nature of the score, general score and approximate score will not change the size of the score

Can we make a general division after the decimals,

Dividing the numerator and denominator of a fraction by their common factor at the same time, the value of the fraction remains unchanged
There are no decimals in the process,
Therefore, should not be about a decimal!

Four numbers 2, 2, 5, 10 have several algorithms to be equal to 24, each number should be used, note that each number can only be used once

The fifth power of 2 is 32
32+2-10=24
（2+2/5）*10=24

How much is (1 + 1 / 2) × (1 + 1 / 3) × (1 + 1 / 4) × (1 + 1 / 5) × (1 + 1 / 10)

Change it to a score
(3/2)*(4/3)*(5/4).*(10/9)*(11/10)
The denominator is left with 2, the numerator is left with 11
11/2

1. (1 + 1 / 2) × (1 + 1 / 3) × (1 + 1 / 4) × (1 + 1 / 5). × (1 + 1 / 10) how much is it

Because 1 + 1 / 2 = 3 / 2
1+1/3=4/3
1+1/4=5/4
……
1+1/10=11/10
Therefore, the original formula = (3 / 2) * (4 / 3) * (5 / 4) * (6 / 5). * (10 / 9) * (11 / 10)
=11/2

How to make the result equal to 1 and 3

4 * 4 / 4-4 / 4 4 / 4 / 4 / 4 / 4 = 1 4 - (4 + 4) / (4 + 4) 4 / 4 / 4 + 4-4 = 16 / 4-1 = 4-8 / 8 = 1 + 4-4
Please accept if you are satisfied

If 1 equals ten, 2 equals 11, 3 equals 12, 4 equals 13, 5 equals 14, 6 equals 15 What's 10, please

A positive m-polygon is just surrounded by a positive n-polygon (no overlap, no gap), as shown in the figure is the case of M = 4, n = 8, if M = 10, then n=______ ．

The degree of the outer angle of a positive decagon is 360 △ 10 = 36 °, so the degree of its inner angle is 180 ° - 36 ° = 144 °, the inner angle of a positive n-polygon is 12 × (360 ° - 144 °) = 108 °, the outer angle of a positive n-polygon is 180 ° - 108 ° = 72 °, and the number of sides of a positive n-polygon is 360 △ 72 = 5

Answer to 100 exercises of solving equations in grade five