Judge whether the two items in each group are similar 1 2A ^ B and 2Ab ^ 2 2 3xy and - 2yx 3 - 2.3 and 2 / 3 4 2a and 2Ab The first one I got wrong was 2A ^ 2B 2Ab ^ 2

Judge whether the two items in each group are similar 1 2A ^ B and 2Ab ^ 2 2 3xy and - 2yx 3 - 2.3 and 2 / 3 4 2a and 2Ab The first one I got wrong was 2A ^ 2B 2Ab ^ 2

1 2A ^ B and 2Ab ^ 2
No, because a and B have different times
2 3xy and - 2yx
Yes, because X and y have the same degree
3 - 2.3 and 2 / 3
Yes, because they are all constant terms, and constant terms are of the same kind
4 2a and 2Ab
No, because one has no B and the other has b

When a (), the multiplication of two A's = 2A; when a (), the multiplication of two A's is greater than 2A; when a (), the multiplication of two A's is less than 2A

When a (= 2 or 0), the multiplication of two A's = 2A; when a (2), the multiplication of two A's is greater than 2A; when a (0), the multiplication of two A's is greater than 2A

2A & # 179; - 8A & # 178; + 12a cross multiplication factorization

2a³-8a²+12a
=2a(a^2-8a+12)
=2a(a-2)(a-6)

If the complex z = (M2 + m-1) + (4m2-8m + 3) I (m ∈ R), the point corresponding to Z is in the first quadrant, the value range of real number m is obtained

The complex z = (M2 + m-1) + (4m2-8m + 3) I, the complex. Z = (M2 + m-1) - (4m2-8m + 3) I corresponds to the point (M2 + M-1, (4m2-8m + 3)) in the first quadrant, then M2 + m − 1 > 04m2 − 8M + 3 < 0, the solution is: − 1 + 52 < m < 32, so the value range of the real number m corresponding to the number in the first quadrant is: − 1 + 52 < m < 32