English translation rt

English translation rt

I like eating apples,bananas grapes and watermelons .
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My name is = = = I like apples and bananas. My friends are = = = and = = = my favorite color is yellow

I like eating snake.I like apple and bananas.my friend like them, too.oh ,my favorite color is yellow,because it can make us warm

When the complex number Z = (m-1) + (2m + 1I,) tries to find the value of the real number m, (1) the point corresponding to Z is on the straight line y = x + 1; (2) the point corresponding to Z is in the fourth quadrant
Sorry, the real problem is: when the complex number Z = (m-1) + (2m + 1) I tries to find the value of the real number m, (1) the point corresponding to Z is on the straight line y = x + 1; (2) the point corresponding to Z is in the fourth quadrant

2 m + 1 = M-1 + 1, M = - 1
2. M - 1 ＞ 0, 2m + 1 ＜ 0, no solution, so it seems that you have a problem
There seems to be a problem if you change it, because the real part of Z is M-1, which corresponds to the real axis, that is, the "x axis". The coefficient of the imaginary part of Z is 2m + 1, which corresponds to the imaginary axis, that is, the "Y axis". Then M-1 should be greater than 0, and 2m + 1 should be less than 0. So there is no solution

If the complex z = (M2 + m-1) + (4m2-8m + 3) I (m ∈ R), the point corresponding to Z is in the first quadrant, the value range of real number m is obtained

The complex z = (M2 + m-1) + (4m2-8m + 3) I, the complex. Z = (M2 + m-1) - (4m2-8m + 3) I corresponds to the point (M2 + M-1, (4m2-8m + 3)) in the first quadrant, then M2 + m − 1 > 04m2 − 8M + 3 < 0, the solution is: − 1 + 52 < m < 32, so the value range of the real number m corresponding to the number in the first quadrant is: − 1 + 52 < m < 32

What does it mean that the module of Z, the module of conjugate complex number of Z and the module of Z are equal?
For example, modules of 1 + I and 1-I are assumed to be positive numbers, but their modules are equal

Module is the root sign of the sum of the square of the real part and the square of the imaginary part, 1 + I is the root sign 2, and 1-I is also the root sign 2
It can also be said that under the root sign (a ^ 2 + B ^ 2)

How to find the real part, imaginary part and module of complex w = (1 + Z) / (1-z)
Z is not equal to 1, Z is a complex number, so the trouble is here. The expression of the answer contains Z. I'll send the answer to you, rew = (1 - | Z | & # 178;) / | 1-z | & # 178;, IMW = 2imz / | 1-z | & # 178;, | w | = under the root sign (1 + | Z | & # 178; + 2rez) / | 1-z |, but I can't deduce such an expression, especially the representation of the imaginary part

(1 + Z) / (1-z) (1-z) = (1 + Z) (1 + Z) / -z \\\\\\\\\\\\\\\\124\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

Complex Z module is 1, Z ^ 2009 + Z ^ 2008 + 1 = 0, find complex Z

If Z ^ 2009 + Z ^ 2008 + 1 = 0, Z ^ 2008 = - 1 / (1 + Z) combined with | Z | = 1, Z ^ 2008 | = 1, then | - 1 / (1 + Z) | = 1, 1 / | - 1 + Z | = 1, so | - 1 + Z | = 1 suppose z = a + bi, there is a & # 178; + B & # 178; = 1 (1 + a) &# 178; + B & # 178; = 1, the solution is a = - 1 / 2, B = ± 1 / 2 * √ 3Z = - 1 / 2 ± 1 / 2 * √ 3I

If the module of complex Z is 2 √ 2 and | Z-2 | = | z-2i |, then Z=____

The results are as follows
Z mode 2 is radical two, so it's on the circle of radius two centered on the origin
And the two modules are equal, which means that the end point is on the perpendicular of (2,0) and (0,2)
So the answer is clear: 2 + 2I - 2-2i
For the best!

What are the common festivals in a year

Spring Festival children's Day Teacher's Day National Day Christmas Day Women's Day
Labor Day Arbor Day

How was your last holiday
What ______ your last vacation _______ ?

What ___ was___ your last vacation _____ like__ ?