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A cylindrical bucket with a bottom radius of 20 cm is filled with water. A cylindrical plumb with a bottom radius of 10 cm is immersed in water when the steel is discharged from the bucket After coming out, the water level in the bucket drops by 3cm. How many cm is the length of the steel? The equation is solved
Let the length of this section of steel be x cm
π×20²×3＝π×10²×x
x＝12
A: the length of this section of steel is 12 cm
In a cylindrical bucket with a bottom radius of 30 cm, a section of cylindrical steel with a radius of 10 cm is completely immersed in water. When the steel is taken out of the water, the water in the bucket drops by 5 cm. How long is this section of steel?
V = sh, = 3.14 × 302 × 5, = 3.14 × 900 × 5, = 14130 (cubic centimeter); 14130 ^ (3.14 × 102), = 14130 ^ (3.14 × 100), = 14130 ^ (314, = 45 (centimeter); a: this section of steel is 45 centimeter long
A cylindrical bucket with a bottom radius of 10 cm is filled with water. After a conical plumb with a bottom radius of 5 cm is immersed in water, the water surface rises by 1 cm without water overflow. How many cm is the plumb height?
The volume of conical lead cone is: 3.14 × 102 × 1, = 314 × 1, = 314 (cm3), the height of lead cone is: 314 × 3 ^ (3.14 × 52), = 942 ^ 78.5, = 12 (CM), a: the height of lead cone is 12cm
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