buoyancy A and B are liquid and solid respectively. The density of liquid a is 1g / cm3, and that of solid B is 0.5g/cm3. When a solid solid (composed of substance B) with a volume of 10-3m3 is put into a container containing enough liquid of substance A, how much buoyancy does the solid solid receive when it is still? How much volume does the liquid displace?

buoyancy A and B are liquid and solid respectively. The density of liquid a is 1g / cm3, and that of solid B is 0.5g/cm3. When a solid solid (composed of substance B) with a volume of 10-3m3 is put into a container containing enough liquid of substance A, how much buoyancy does the solid solid receive when it is still? How much volume does the liquid displace?


Because the density of solid B is 0.5g/cm3, and the density of liquid a is 1g / cm3, a solid solid composed of substance B is put into a container with enough substance A. when the substance B is still, the floating buoyancy = gravity = PGV = 500kg / m3 * 9.8N / kg * 0.001m3 = 4.9n, the volume of liquid f floating = PGV = 1000kg / m3



On buoyancy
Now there is a hollow toothpaste skin, a large glass of water and a measuring cylinder. Please design an experiment to calculate the density of toothpaste skin
There's no balance, no spring dynamometer or anything~
Because this is the connection of buoyancy chapter, it is estimated that it is related to buoyancy~
First thx~


Try this:
Fill the measuring cylinder with proper amount of water and record the scale v0
Immerse (sink) all the toothpaste skin in the water of the measuring cylinder (the hollow part also has water), and record the scale v1
Toothpaste skin volume = v1-v0
Take out the toothpaste skin, do not take out the water in the hollow part, let it float in the water of the measuring cylinder (there is no water in the hollow part), and record the scale
Volume of water discharged from toothpaste skin = v2-v0
G = f = water density × g × (v2-v0) toothpaste skin mass = water density × (v2-v0)
Toothpaste skin density = water density × (v2-v0) / (v1-v0)
Typing good trouble, tired s... I hope you can understand
come on.
How can I do it, someone answered? I won't answer later, typing is slow



All the scientific formulas in Volume I of the second grade of junior high school should be handed in, and the deformation formula should also include,,,, buoyancy
Don't be too stingy, want the final exam ~ ~ ~ the topic is wrong, all of them have to be!!!


Density ρ = m / V pressure P = f / s buoyancy ① f floating = g – f ② floating and suspending: F floating = g ③ f floating = g row = ρ liquid g V row series circuit current I (a) I = I1 = I2 = The current is equal everywhere and the voltage U (V) u = U1 + U2 + The series circuit acts as a voltage divider, and the resistance R (Ω



Someone uses a movable pulley to lift a bucket of water 0.5m high at a constant speed with a force of 100N. At the same time, the length of the rope is 1m. How much work has he done in this process?


What is the velocity of uniform velocity? If kinetic energy and energy loss are not considered, all the work done by that person is converted into the gravitational potential energy of the barrel, EP = mg △ H = f · s = 100 * 1 = 100J



Junior high school physics all electrical and pulley formula. To all! To have applicable conditions! And explain each formula


Speed formula physical quantity calculation formula international main unit common unit conversion relation speed v v v = s / T m / s km / h 1m / S = 3.6km/h distance s s s = VT m km 1km = 1000m time t t t = s / v s h 1H = 60min = 3600s distance s when a train crosses a bridge (tunnel)



The problem of solving various mechanical efficiency of pulley in Physics
Like the title,


Vertical pulley block (picture: one fixed pulley, two movable pulleys, starting point on fixed pulley, n = 4)
Xiaoming uses pulley block to pull up a 600N object. The object rises by 2m. The force Xiaoming uses is 200N and the mechanical efficiency of pulley block (pulley weight and rope friction are ignored)
Known: g = 600N, H = 2m, f = 200N, n = 4
For: η
Gh Gh 600N*2m
η=——*100%=——*100%=-----------*100%=75%
Fs Fns 200N*4*2m
A: the mechanical efficiency of this pulley block is 75%



As shown in the figure, the weight and friction of the rope are not included: (1) please use the three pulleys shown in the figure to make up the complete winding of the pulley block; (2) when the weight of the object is 50N, the rope end needs 20n tension to make the object rise at a uniform speed. What is the mechanical efficiency of the pulley block at this time? (3) When the weight of the rope is 90N, how much tension is needed to make it rise at a constant speed? (4) If the maximum tension that the rope can bear is 60N, how many objects can the pulley block lift?


(1) Fix one end of the rope on the hook of the fixed pulley, and then wind it in turn, as shown in the figure below: (2) at this time, the mechanical efficiency of the pulley block: η = w, W, total × 100% = ghfs × 100% = g4f × 100% = 50n4 × 20n × 100% = 62.5%; (3) the weight and friction of the rope are not included. According to f = 14 (G + G dynamic), the gravity of the moving pulley block: G dynamic = nf-g = 4 × 20n-50n = 30n, when the weight is 90N, the rope end needs to be adjusted (4) if the maximum tension the rope can bear is 60N, the maximum lifting weight is: G ″ = 4f ″ - gdynamic = 4 × 60n-30n = 200N. (2) when the weight is 50N, the rope end needs 20n tension to make the object rise at a uniform speed, and the mechanical efficiency of the pulley block is 62.5%; (3) when the weight is 90N, the rope end needs 30n tension (4) if the maximum tension the rope can bear is 60N, the pulley block can lift 200N objects



A problem of physical pulley and mechanical efficiency,
As shown in the figure, under the action of tensile force F, object a moves in a straight line at a speed of 5cmgs on the horizontal ground at a constant speed. At this time, the indication of spring force and is 3N. The mechanical efficiency of pulley is 75%. Find out (1) the size of friction force F and tensile force F on object a
The picture shows a moving pulley rope with one free end pulling object a horizontally, the other end pulling spring to measure the force, and the other end of the spring dynamometer is fixed on the wall
The answer given in the book is f = 4.8n. How can we calculate it?
I don't have permission to insert pictures. Is there any other way


The decomposition of stress condition is related to stress angle, stress condition and so on



What are the formulas of pulley block?


Mechanical efficiency of pulley block: (ignoring rope weight and friction)
When used to lift heavy objects: η = wyou / wtotal
=G / n.f
=G object / g object + G motion (g motion is the weight of moving pulley)
=Gh/Fs
When it is used to move objects horizontally (i.e. to overcome friction)
η = F.S object / F.S rope
=F / N. f (F is the friction force on the object, s is the object, s is the distance that the object and the rope move respectively)



Let f (n) = 2n + 1 (n belongs to n *), G (n) = 3 when n = 1, G (n) = f (g (n-1)) when n > = 2, find the general formula of G (n)


n> G (n) = 2g (n) = f (g (n-1)) g (n) = 2g (n-1) + 1g (n) + 1 = 2 [g (n-1) + 1] (n > = 2) because g (1) = 3, G (1) + 1 = 4, so {g (n) + 1} is an equal ratio sequence with G (1) + 1 = 4 as the first term and 2 as the common ratio. So g (n) + 1 = 4 * 2 ^ (n-1) = 2 ^ (n + 1) (n > = 1, belonging to n *). Therefore, the general formula of G (n) is: G (n) = 2 ^ (n + 1