There are six big cylindrical columns in the lobby of a hotel. The perimeter of the columns is 25.12dm. All of them need to be painted. If the painting fee is 80 yuan per square meter, it will cost more It's due tomorrow. It's a formula

In fact, what is painted is the side area of six cylinders
So there are:
80 * (25.12 / 10) * 10 * 6 = 12057.6 yuan
That is, it costs 12057.6 yuan

A conference hall has eight large cylindrical columns with a perimeter of 2.5 meters at the bottom and a height of 5 meters,
According to a kilogram of paint can paint 4 square meters, finish how much paint

Surface area of each column = 2.5 × 5 = 12.5 square meters
Surface area of 8 columns = 8 × 12.5 = 100 square meters
100 △ 4 = 25 kg
A: it takes 25 kg of paint to finish

The perimeter of the bottom surface of the cylindrical warehouse is 75.36 meters, and the height is 10 meters. What is the area to be painted when painting its surroundings and the ground?
Plus: if each cubic meter of wheat weighs 800 kg, how many tons can this warehouse hold? Thank you!

Question 1: 75.36 * 10 = 753.6 (M2)
3.14 * (75.36 / 3.14 / 2) m2 = 452.16 (M2)
753.6 + 452.16 = 1205.76 (M2)
Question 2: 452.16 * 10 = 4521.6 (M3)
4521.6 * 800 = 3617280 (kg) = 3617.28 (T)
I've been calculating for a long time. I should be right

There are six big cylindrical columns in the lobby of a hotel. The perimeter of the columns is 25.12dm. All of them need to be painted. If the painting fee is 80 yuan per square meter, it will cost more It's due tomorrow. It's a formula