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If the height of a cube is increased by 2 cm, the surface area of the cube will be increased by 96 square cm. What is the original volume surface area? What is the volume surface area of the original cube?
Let the original edge of a cube be X
*It's a multiple sign
4*2*x=96
The solution is x = 12
Surface area of cube = 12 * 12 * 6 = 964 square centimeter, length times width times 6
Cube volume = 12 * 12 * 12 = 1728 square centimeters, length times width times height
The surface area of a cube is 96 square centimeters. Divide it into two cuboids averagely. How many square centimeters is the surface area of each cuboid?
The surface area of the cube is 96 square centimeters
Square area = 96 / 6 = 16 square centimeter
Square side length = 4cm
The surface area of each cuboid is 2 × 4 × 4 + 4 × 4 × 2 = 64 square centimeters
If a cube with a surface area of 96 square centimeters is cut into two identical cuboids, the surface area of each cuboid is______ Square centimeter
Answer: the surface area of each cuboid is 64 square centimeter
If the height of a cube increases by 2 decimeters, it will become a cuboid. The surface area of the cuboid will increase by 96 square decimeters compared with the original cuboid. What is the volume of the original cuboid?
The original cube's edge length: 96 △ 4 △ 2 = 12 (decimeter), 12 × 12 × 12 = 1728 (cubic decimeter); answer: the original cube's volume is 1728 cubic decimeter
1. Divide a cube into two parts equally. Given that the surface area of each cuboid is 96 square centimeters, how much is the surface area of the original cube?
2. The surface area of a cuboid with a length of 6cm, a width of 4cm and a height of 3cm is calculated after a cube with a length of 2cm is dug out?
3. There is a cube whose edge length is 5cm. After digging a cube whose edge length is 1cm from its top, what is the remaining surface area?
1. Dividing into two parts means increasing the surface area of two squares, 96 / 8 * 6 = 72 square centimeters; 2. If it is excavated on the surface, it is equivalent to increasing the original surface area of four squares with side length of 2 centimeters; (4 * 6 + 3 * 6 + 3 * 4) * 2 + 2 * 2 * 4 = 224 square centimeters; if it is excavated on the inside without sticking to the surface
A cuboid pool, covering an area of 16 square meters, with a depth of 1.6 meters. If a layer of cement is plastered on the four sides and the bottom, the area of plastering cement is []
16*1.6=25.6(M^2)
Side up!
A pool with a square bottom is 2 meters deep. If the pool can hold 11.52 cubic meters of water, the bottom of the pool will be closed
A pool with a square bottom is 2 meters deep. If the pool can hold 11.52 cubic meters of water, what is the side length of the bottom of the pool?
Bottom area 11.52 △ 2 = 5.76 square meters
5.76=2.4×2.4
So the bottom side length is 2.4 meters
The perimeter of a circular fountain is 62.8 meters. There is a 1 meter wide circular cement road outside the fountain. How many square meters is the area of the circular road?
To plant a circle of grass on the periphery of the concrete road, how many meters is the total length of the circle of grass?
Radius of spray tank: 62.8 ÷ (2 × 3.14) = 10m,
The area of circular road is the area of circular ring: 3.14 × (11 ^ 2-10 ^ 2) = 65.94 square meters,
The length of grass is the circumference: 2 × 3.14 × 11 = 69.08m
The perimeter of a circular fountain is 62.8 meters. There is a cement road 0.5 meters wide outside the fountain. How many square meters is the pavement area
Radius: 62.8 ﹣ 3.14 ﹣ 2 = 10m
Road area: 3.14 × (10 + 0.5) & # 178; - 3.14 × 10 & # 178; = 32.185 M2
A 2m wide cement road is laid around a 10 meter diameter circular fountain. What is the area of this cement road
A 1-meter-wide cement road is laid around a circular fountain with a diameter of 4 meters. What is the area of the cement road? If 900 kg is used per square meter, how much sand is required?
(1) Original radius r = 10 △ 2 = 5m, current radius r '= 5 + 2 = 7m, cement road area = π R' &# 178; - π R & # 178; = π (R '&# 178; - R & # 178;) = π (7 & # 178; - 5 & # 178;) = 24 π = 75.36 (M2) answer: the area of this cement road is 75.36 M2 (2) original radius r
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