Now I'm in the second year of junior high school. I want to buy a physics book. Please introduce it to me Such as the title, recommend good I give bonus points!

Now I'm in the second year of junior high school. I want to buy a physics book. Please introduce it to me Such as the title, recommend good I give bonus points!


My first choice is to buy my second and third grade. It's really good. The shell of the second grade seems to be green. If you buy it, you must watch it. I insist on reading every day in the second grade. Buoyancy is easy to win. But my third grade learning task is a little heavy. I can't just learn physics. Although I bought it, I didn't see anything, but I learned in the second grade



In order to find out the relationship between the vibration amplitude of the steel body on and off the table, he used a steel ruler to keep a certain degree of vibration amplitude The louder the conclusion is, what do you think is his mistake in collecting evidence______ .


In the experiment, the eye observes the vibration amplitude of the steel ruler and the ear listens to the loudness produced by the vibration of the steel ruler. We are not studying the vibration amplitude and loudness of the table, and we can't collect the sound of the table



After resistor R1 and R2 are connected to the circuit in series, the voltage applied at both ends is 24 v. if R1 is 80 Ω, the current passing through R2 is 0.2 a, R2 can be calculated. Can you find out the answer in two ways?


Method 1: ∵ the current in all parts of the series circuit is equal, ∵ according to Ohm's law, the total resistance in the circuit is r = UI = ui2 = 24v0.2a = 120 Ω, ∵ the total resistance in the series circuit is equal to the sum of the partial resistances, ∵ R2 = r-r1 = 120 Ω - 80 Ω = 40 Ω. Method 2: ∵ the current in all parts of the series circuit is equal, ∵ according to Ohm's law, the voltage at both ends of R1 is U1 = i1r1 = i2r1 = 0.2A × 80 Ω = 16 5. ∵ the total voltage in the series circuit is equal to the sum of the partial voltages, and the voltage at both ends of R2: U2 = u-u1 = 24 V-16 v = 8 V, then R2 = u2i2 = 8 V 0.2A = 40 Ω. Answer: the resistance value of R2 is 40 Ω