If LG2 = a, what is log2 (5)?

log2(5)=(lg5)/(lg2)
=[lg(10/2)]/(lg2)
=(1-lg2)/lg2
=(1-a)/a

Log27 (16) divided by log3 (4) =?

The formula for changing the bottom is as follows:
log27（16）÷log3（4）
=（lg16/lg27）÷（lg4/lg3）
=（4/3lg2/lg3）÷（2lg2/lg3）
=4/3÷2
=2/3

It is known that log3 10 = a, log27 25 = B, and LG 5 is represented by a and B

log3(10)=a lg3=1/a
log27(25)=b
lg25/lg27=b
2lg5/(3lg3)=b
lg5=3blg3/2=3b/(2a)

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