Find the range of function y = ㏒ 2 (3x & # 178; - 5x + 17)

Find the range of function y = ㏒ 2 (3x & # 178; - 5x + 17)

Let 3x ^ 2-5x + 17 = t
The minimum value of T is 179 / 12
When Tmin = 179 / 12 in y = log2 (T)
And because y = log2 (T) is a monotone increasing function
ymin=log2(179/12)
So the range is (log2 (179 / 12), positive infinity)

Calculation of logarithmic function in Senior High School
What is the value of lg5 (LG8 + lg1000) + (LG2 ^ √ 3) ^ 2 + LG1 / 6 + lg0.06?

Original formula = lg5 (LG2 & sup3; + LG10 & sup3;) + (√ 3lg2) & sup2; + LG (1 / 6 × 0.06)
=lg5(3lg2+3lg10)+3lg²2+lg(0.01)
=3lg2lg5+3lg5+3lg²2+(-2)
=3lg2(lg5+lg2)+3lg5-2
=3lg2+3lg5-2
=3(lg5+lg2)-2
=3-2
=1

High school logarithm function operation
lg5*lg8000+3(lg2)2+lg（1\6)+lg0.06
(LG2) 2 is the square of LG2

lg5*lg8000+3(lg2)2+lg（1\6)+lg0.06
=lg5*lg8*(10)3+3(lg2)2-lg6+lg6*[(10)-2]
=lg5*[3*lg2+3]+3(lg2)2-lg6+lg6-2
=3(lg2)2+3*lg5*lg2+3*lg5-2
=3*lg2（lg2+lg5）+3*lg5-2
=3*lg2+3*lg5-2
=3-2
=1