A train passes through two tunnels at the same speed. The first 420 meters takes 27 seconds, and the second 480 meters takes 30 seconds?

A train passes through two tunnels at the same speed. The first 420 meters takes 27 seconds, and the second 480 meters takes 30 seconds?


(480-420) / (30-27) = 20 m / S
20 × 30-480 = 120m
A: the train is 120 meters long and the speed is 20 meters per second



A train runs through two tunnels at the same speed. The first tunnel is 420 meters long, which takes 27 seconds; the second tunnel is 480 meters long, which takes 30 seconds to find out the length of the train
How many meters does the train travel per second


The length of the train is x meters
Then (x + 420) × 27 = (x + 480) × 30
30(X+420)=27(X+480)
30X+12600=27X+12960
3X=360
X=120
The train runs (120 + 420) △ 27 = 20m per second



A train passes a bridge and a tunnel at the same speed. It is known that the bridge length of the bridge is 420 meters, and it takes 27 seconds. The length of the cableway is 480 meters, and it takes 30 seconds. Try to find out the speed of the train and the length of the train
Solve by equation
(-1001)^2009×(0.125)^2008×(-2/7)^2009×(-4/13)^2009×(-1/11)^2009


Let the conductor be X,
The distance to cross the bridge is 420 + X, and the distance to cross the cableway is 480 + X
Then the speed of the train is (420 + x) / 27 or (480 + x) / 30
That is: (420 + x) / 27 = (480 + x) / 30
The solution is: x = 120, (420 + x) / 27 = 20
That is, the length of the train is 120 meters and the speed of the train is 20 meters per second