A train is 200 meters long and has to pass through a 300 meter long tunnel. How many meters does the train travel from the front to the rear of the train?

A train is 200 meters long and has to pass through a 300 meter long tunnel. How many meters does the train travel from the front to the rear of the train?


Driving distance = 200 + 300 = 500m
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The length of a railway tunnel is 1000m. The average speed of a 200m long train passing through the tunnel is 2min. The speed of the train passing through the tunnel can be calculated
How long does the train stay in the tunnel


1. The speed of the train is: (1000 + 200) △ 120 = 10 m / s;
2. The total time of the train in the tunnel is (1000-200) △ 10 = 80 seconds



A train has 20 sections, each section is 5 meters long, and the distance between the two sections is 1 meter. It takes several minutes for the train to pass through the 81 meter tunnel at a speed of 200 meters per minute


[20x5 + 1x (20-1) + 81] △ 200 = 1 (minutes)
A: it takes a minute for the train to pass through the tunnel



A train has 20 sections, each section is 5 meters long, and the distance between the two sections is 1 meter. It takes several minutes for the train to pass through the 81 meter long tunnel at the speed of 200 meters per minute


v=200m/min=10/3m/s s=[(20x5)+19x1]+81=200m s=vt t=s/v=200x(3/10)=60s=1min



A train has 20 sections, each section is 5 meters long, and the distance between the two sections is 1 meter. How many minutes does it take for the train to pass through the 81 meter long tunnel at the speed of 20 meters per minute?


Train length = 20x5 + 19x1 = 119m
Time required = (119 + 81) △ 20 = 10 minutes



A train has 20 sections, each section is 5 meters long, and each section is 1 meter apart. How many minutes does it take for this train to pass through the 81 meter tunnel at 200 meters per minute?


1 minute



What's the speed of a train passing through a 250m tunnel in 25 seconds and a 210m tunnel in 23 seconds


(250-210)÷(25-23)
=40÷2
=20 m / S



It takes 18 seconds for an average speed train to enter the 320m long tunnel and pass through the tunnel completely. There is a gap at the top of the tunnel
one
It takes 18 seconds for an average speed train to enter the 320m long tunnel and pass through the tunnel completely. There is a light on the top of the tunnel shining vertically on the train for 12 seconds. How long is the train?


Let the conductor be x and the speed be v
{320+X=18V
12V=X
X=640
The train is 640m long



It takes 18 seconds for a train to enter a 320m long tunnel and pass through the tunnel completely. There is a fixed light on the top of the tunnel, which shines vertically downward. If the light shines on the train for 10 seconds, the length of the train is______ m.


Let the speed of the train be YM / s. according to the meaning of the question, we get: 320 + 10Y = 18y, we get: y = 40m, we get: the length of the train is: 40 × 10 = 400m



It takes 80s for a 200m train to pass through the tunnel, and the known speed is 50M / s


80 * 50-200 = 3800m, this 80s includes the length of the train itself