How long does a 100 meter long train go through a 500 meter long cave at a speed of 72 km / h? Thank you

How long does a 100 meter long train go through a 500 meter long cave at a speed of 72 km / h? Thank you


(500+100)/72=25/3



The 200m long train runs at a constant speed of 43.2km/h on the Beijing Kowloon line. When it crosses the 1000m long tunnel, the time required is______ .


The distance of the train: S = S1 + S2 = 200m + 1000m = 1200m, the speed of the train: v = 43.2km/h = 12m / S; the time of the train: T = SV = 1200m, 12m / S = 100s; so the answer is: 100s



How long does it take for a 150m long train to cross a 130m long train traveling in the same direction at a speed of 5m / s when it moves at an average speed of 54km / h
How long does it take for a 150m long train to cross a 130m long train traveling in the same direction at a speed of 5m / s with an average speed of 54km / h?


54km / h = 15m / s, with the team as the reference, then the speed of the train is 15-5 = 10m / s, the distance of the train passing through the team is 130 + 150 = 280m, so the required time is 280 / 10 = 28s



A passenger is sitting in a train with a speed of 54 km / h, and a 150 m long freight car with a speed of 36 km / h comes from the parallel track,
How long does it take for the truck to pass the passengers? I don't understand the online method.)


This is a problem of relative speed. As passenger cars and freight cars are running in opposite directions, we can think that the speed of freight cars relative to passengers is (36 + 54) km / h = 90km / h, and the change unit is 90 / 3.6 = 25m / s. therefore, the time for a 150m long freight car to pass passengers should be t = 150 / 25 = 6 seconds



It takes 10 seconds for a 30 meter long train to pass a 70 meter long bridge at a constant speed. If it takes 3 minutes to pass another bridge at the same speed, how long is the bridge?


When the first train crosses the bridge, the total distance is s = 30m + 70m = 100m, and the speed is v-car = st = 100m10s = 10m / s. when the second train crosses the bridge, the total distance is s-bridge + s-car = v-car × T1 = 10m / s × 180s = 1800m. So s-bridge = 1800m-s-car = 1800m-30m = 1770m. A: the bridge is 1770m long



It takes 10 seconds for a 150 m long train to pass through a 90 m long bridge at a uniform speed. The calculation is as follows: (1) the speed of the train. (2) how long does it take for the train to pass through a 1050 m long tunnel at the same speed


(1) V = st = 150m + 90m10s = 24m / s a: the speed of the train is 24m / S; (2) t = SV = 1050m + 150m24m / S = 50s. A: it takes 50 seconds for the train to cross a 1050m long tunnel at the same speed



A car runs at a constant speed and passes a 150 m long iron bridge in 10 seconds. How long does it take for it to pass a 4500 m highway at such a speed?


Given: S1 = 150m, time T1 = 10s, highway length S2 = 4500m, time T2 =? The driving speed of the car is v = s1t1 = 150m10s = 15m / s, ∵ v = st, ∵ the time for the car to pass a 4500m highway is T2 = S2V = 4500m15m / S = 300s. A: it takes 300s for the car to pass a 4500m highway at this speed



How long does it take for a 200m long light rail train to cross a 2.8km overpass at a speed of 15km/s?


From the time when the front of the car arrives at the end of the bridge to the time when the rear of the car leaves the end of the bridge
2.8km=2800m
t=(2800+200)/15=200s



A 200m long train passes through a 1km long train bridge at a speed of 40m / s. how long does it take for the train to get on the bridge and leave the bridge? If the train driver sees himself on the bridge, how long does it take for him to get off the bridge?


If the bridge is 1000 meters long and the train is 200 meters long, the distance from the train on the bridge to the train leaving the bridge is 1000 + 200 = 1200 meters
The speed of the train is 40 m / s, so the time required for the train to pass the bridge is 1200 △ 40 = 30 seconds
When a train driver sees himself on the bridge, the distance he travels from getting off the bridge is 1000 meters
Then the time used is: 1000 △ 40 = 25 seconds



A 200m long train runs at a speed of 14.4km/h and takes 130s to cross a cave. What is the length of the cave?


Cave length: 320 meters
14.4 * (1000 / 3600) * 130-200 = 320m
Let's take it