It took 50 seconds for a train to pass through a 1140 meter long bridge (from the front of the train to the rear of the train leaving the bridge), and 80 seconds for the train to pass through a 1980 meter long tunnel?

(1980-1140) △ 80-50, = 840 △ 30, = 28 (M / s); & nbsp; 28 × 50-1140, = 1400-1140, = 260 (m). A: the speed of this train is 28 m / s and the length of its body is 260 M

The train passes through a 200 meter long tunnel. It takes 10 seconds for the front of the train to enter and the rear of the train to come out. The body of the train is 50 meters long. What is the random degree of the train?
Use equation solution, with: suppose, quantity relation. Quantity relation may not exist. Equation should be detailed

Set the vehicle speed to x m / s,
The distance moved by the rear of the car is 50 + 200 = 250 meters
Equation 10x = 50 + 200
The solution is x = 25
The speed of the train is 25 meters per second

It takes 30 seconds for a train to enter a 600 meter long tunnel from the front to leave the rear. It is known that the time for a fixed light at the top of the tunnel to shine vertically on the train is 5 seconds, so how long is the train?

Let x = 120 + 5 m be the length of the train

A train moving at a constant speed, from he began to enter the 300m long tunnel to completely pass through the tunnel for 18S, there is a fixed light at the top of the tunnel
After 10 seconds on the train, how long is the train

The speed of the train is 300 △ 10 = 30 meters per second
The length of the train is: 30 × (18-10) = 240 meters

It takes 18 seconds for a train running at a constant speed to enter the 320 meter long tunnel and pass through it completely. A fixed light at the top of the tunnel shines on the train for 10 seconds. How long is the train?

Suppose the length of this train is x meters, according to the meaning of the title: 320 + x18 = X10, the solution is: x = 400

A train goes through the 320 meter long tunnel at a constant speed. It takes 18 seconds. A fixed light at the top of the tunnel shines vertically on the train
It takes 18 seconds for a train to pass through a 320 meter long tunnel at a constant speed. There is a fixed light at the top of the tunnel. The vertical illumination time on the train is 10 seconds. How many meters is this train? (using equation solution)

If the length of the train is x meters, the total distance is a tunnel and the length of a train is (320 + x) meters, and the speed on both sides of the equal sign is equal, then:
（320+X）/18=X/10
The solution is x = 400
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It takes 30 seconds for a train to go through the 450 meter tunnel at an average speed. At the top of the tunnel, a fixed light shines vertically on the train for 10 seconds to calculate the length of the train
Specific!
Urgent need!!

If the train is long x, then its speed can be expressed in two ways: (x + 450) / 30 and X / 10. Because of the uniform speed, they are equal, that is to say
(x+450)/30=x/10
The solution is x = 225

It takes 18 seconds for an average speed train to enter the 320m long tunnel and pass through it completely. The time for a fixed light on the top of the tunnel to shine vertically on the train is 10 seconds. How long is the train?
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Let v be the train speed and X be the train length
18v＝320＋x
10v=x
The solution is: v = 40, x = 400
So the length of the train is 400 meters

Train length and speed: there is a tunnel with a total length of 1500 meters. It takes 55 seconds for a train to enter the tunnel and walk out of the tunnel completely, while the time for the whole train in the tunnel is 45 seconds

Let the train length be x m, (1500 + x) / 55 = (1500-x) / 45
The solution is x = 150m
So the velocity v = 30m / s

It takes 19 seconds for a train to pass through a 300m long tunnel at a uniform speed
There is a telephone booth next to the tunnel. The time for the train to pass through the telephone booth is 9 seconds. Find the length and speed of the train [use the equation!]

Let the length of the train be x, the speed be y, and the train be uniform
19*Y=300+X
X/9=Y
Solve the equation, x = 270, y = 30

It took 50 seconds for a train to pass through a 1140 meter long bridge (from the front of the train to the rear of the train leaving the bridge), and 80 seconds for the train to pass through a 1980 meter long tunnel?