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A 200m long train takes 45s to cross a 700 long bridge. What is the average speed of the train passing the bridge?
（200+700）/45
=20m/s
=72km/h
A train is 200 meters long and moves in a straight line at a constant speed. It takes 100 seconds for the whole train to cross the 1.8 ㎞ long bridge. What's the speed of the train
200m = 0.2km (first unified unit)
（1.8 + 0.2 ） = 2km
2 / 100 = 0.02 (km / h) = 20 (M / h)
A: the speed of the train is 20 m / h
A 200 meter long train takes one minute to cross a 1000 meter long bridge. What's the speed of the train, km / h
= =
This 200 meter train has traveled 1200 meters through the 1000 meter bridge, which is 1.2 kilometers
One minute is one in sixty
1.2 divided by 1 / 60 equals 72 km / h
So the speed of passing the bridge in one minute should be 72 km / h
How long does it take for a 200m long light rail train to pass through a 2.8km overpass at a speed of 15mgs?
The distance for the train to completely pass the bridge: S = l bridge + L car = 200m + 2.8 × 103m = 3000m, the time for the train to completely pass the bridge: T = st = 3000m, 15m / S = 200s
A railway is 1200 meters long. There is a train passing over the bridge. It is measured that it takes 50 seconds for the train to completely cross the bridge, and the time and time of the whole train bending on the bridge
A railway is 1200 meters long. There is a train passing over the bridge. It takes 50 seconds for the train to cross the bridge completely. The time for the whole train to be on the bridge is 30 seconds. The length and speed of the train can be calculated
The train was completely on the bridge for 30 seconds and passed for 50 seconds
It took 10 seconds to get on the bridge and 10 seconds to get off the bridge
The speed of the train is 30 meters per second and the length of the train is 300 meters
The total length of a bridge is 6800m, and there is a 200m long train passing through the bridge at the speed of 72km / h
(1) the time taken for the train to pass through the bridge
(2) The time when all trains are on the bridge
(3) Time taken for passengers on the train to pass the bridge
1 350 seconds; 2 330 seconds; 3 340 seconds 1, when the rear of the car is 200 meters away from the bridge, the front of the car arrives on the bridge, and the time starts. When the rear of the car leaves, the total distance is 200 + 6800 meters = 7000 meters, and the speed is 20 meters per second, and the time is 7000 / 20 = 350 seconds. 2 the rear of the car starts to time on the bridge, and when the front of the car just leaves the bridge, the time stops, and the rear of the car leaves the bridge 20 seconds
The total length of a bridge is 6800m. There is a 200m long train running at a speed of 72km per hour. The time for all trains to pass the bridge. The time for all trains to pass the bridge. The time for all trains to pass the bridge
One 7000 divided by 20 is 350 seconds
The train is 150m long and passes the 450m long bridge at a constant speed. The driver finds that it takes 10s for him to pass the 200m river. How long does it take for the train to pass the bridge? (in physical writing format, brought in by formula)
High school physics is a strong point, you must write full marks. From the meaning of the question, the train speed: v = s / T = 200m / 10s = 20m / s, so the train through the bridge time: 450m + 150m / 20m / S = 30s
There is a 200m long train passing through the bridge. It takes 1min for the train to get on the bridge and get off the bridge completely. The duration of the whole train completely on the bridge is 40s. The length and speed of the bridge can be calculated
Using [[binary linear equation]]
It's better to write down why,
If the equation is wrong and the bridge is only 40 meters long, how can the whole train be completely on the bridge?
Should be:
If the length of the bridge is x and the train speed is y, then (1min is converted into 60s)
X-200=40Y
(the whole train is completely on the bridge for 40s, which refers to the period from the time when the rear part of the train goes on the bridge to the time when the front part of the train goes off the bridge. When the rear part of the train goes on the bridge, the front part of the train has already been on the bridge for 200m, so the distance the train travels is the bridge length vehicle length.)
X+200=60Y
(from the beginning of getting on the bridge to getting off the bridge completely, the front of the train has to travel another 200m after passing the bridge, and then the rear of the train gets off the bridge, that is, getting off the bridge completely. So the distance the train travels is the length of the bridge + the length of the train.)
Solve the equation, x = 1000, y = 20
A: the bridge is 1000m long and the speed is 20m / s
A bridge is 3600m long, a 200m long train passes the bridge at the speed of 36km / h, how long does it take for the train to completely pass the bridge
If it takes 5 minutes for the train to pass through a cave, how long is the cave?
The movement distance of the bridge is the length of the bridge plus the length of the car, so
t = (3600 + 200)/(36 / 3.6) = 380s
5 * 60 = (L + 200)/10,L = 2800m
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