A train runs at a constant speed through a 500m long tunnel, If it takes 30 seconds for the train to enter the tunnel and leave the tunnel completely, and the time for the whole train to be in the tunnel is 20 seconds, the length of the train can be calculated Using equation

A train runs at a constant speed through a 500m long tunnel, If it takes 30 seconds for the train to enter the tunnel and leave the tunnel completely, and the time for the whole train to be in the tunnel is 20 seconds, the length of the train can be calculated Using equation


(500+X)/30=X/((30-20)/2)
(500+X)/30=X/5
500+X=6X
5X=500
X=100



It takes 20 seconds for a train to run at a constant speed through a 300m long tunnel. There is a light on the top of the tunnel, which lights vertically downward. If the light shines on the train for 10 seconds, then the speed of the train is______ .


Let the length of the train be x, from the meaning of the question: 300 + X20 = X10, the solution is: x = 300, then the speed of the train is 300 △ 10 = 30m / s. answer: the speed of the train is 30m / s. so the answer is: 30m / s



It takes 20 seconds for a train to run at a constant speed through a 300m long tunnel. There is a light on the top of the tunnel, which lights vertically downward. If the light shines on the train for 10 seconds, then the speed of the train is______ .


Let the length of the train be x, from the meaning of the question: 300 + X20 = X10, the solution is: x = 300, then the speed of the train is 300 △ 10 = 30m / s. answer: the speed of the train is 30m / s. so the answer is: 30m / s



It takes 20 seconds for a train to travel at a constant speed through a 300m long tunnel. There is a lamp on the top of the tunnel, which lights down vertically. The time of the lamp shining on the train is 10 seconds. (1) suppose the length of the train is XM, expressed by the formula containing X: the distance and average speed of the train from the front to the rear of the train passing under the lamp; (2) suppose the length of the train is XM The length is XM, which is expressed by the formula containing X: the distance and average speed of the train from the front of the train entering the tunnel to the rear of the train leaving the tunnel; (3) has the average speed of the train changed in the above question? (4) Find the length of the train


(1) According to the meaning of the question, the distance from the front of the train passing under the light to the rear of the train passing under the light is XM, and the average speed of the train in this period is x10m / S; (2) the distance from the front of the train entering the tunnel to the rear of the train leaving the tunnel is (x + 300) m, and the average speed of the train in this period is x + 30020m / S; (3) the speed has not changed; (4) according to the meaning of the question, the distance from the front of the train entering the tunnel to the rear of the train leaving the tunnel is (x + 300) m, and the average speed of the train+ If x = 300, the length of the train is 300m



It takes 20 seconds for a train to run at a constant speed through a 300 m long tunnel. There is a light on the top of the tunnel, which shines vertically downward. When the light is shining on the train, it will take 20 seconds
According to the above data, can you find out the length of the train? If so, what is the length of the train? If not, please explain the reason


The length of the train can be obtained
Let the length of the train be x meters
(300+x)/20=x/10
x/20=15
x=300
A: the length of the train is 300 meters
What our math teacher said recently is absolutely right



It takes 20 seconds for a train to travel at a constant speed through a 300m long tunnel. There is a lamp on the top of the tunnel, which lights vertically downward,
The time of the light shining on the train is 101. Let the length of the train be x meters, which is expressed by the formula containing X: the distance of the train and the average speed of the train in this period
2. Let the length of the train be x meters, expressed by the formula containing x; the distance the train takes from the front of the train entering the tunnel to the rear of the train leaving the tunnel and the average speed of the train during this period
3. Has the average speed of the train changed in the above question?
4. Find the length of the train
Process and those with equivalent relationship should have equivalent relationship


X 30 300 + x 300 + x ^ 2 has no 300,



It takes 20 seconds for a train to run at a constant speed through a 300m long tunnel. There is a light on the top of the tunnel, which lights vertically downward. If the light shines on the train for 10 seconds, then the speed of the train is______ .


Let the length of the train be x, from the meaning of the question: 300 + X20 = X10, the solution is: x = 300, then the speed of the train is 300 △ 10 = 30m / s. answer: the speed of the train is 30m / s. so the answer is: 30m / s



It takes 20 seconds for a train to travel at a constant speed through a 300 meter long tunnel. There is a lamp on the top of the tunnel, which lights down vertically. The time that the lamp shines on the train is 10 seconds. Find the length of the train


Suppose the length of the train is x meters. From the meaning of the question, we get 300 + x 20 = x 10. The solution is: x = 300. A: the length of the train is 300 meters



It takes 20 seconds for a train to travel at a constant speed through a 300m long tunnel. There is a lamp on the top of the tunnel, which lights the train vertically
Q 1. Let the length of the train be x, which is expressed by the formula containing X: the distance and average speed of the train from the front of the train passing under the light to the rear of the train passing under the light; 2. Let the length of the train be x, which is expressed by the formula containing X: the distance and average speed of the train from the front of the train entering the tunnel to the rear of the train leaving the tunnel;


1. Distance: x m speed: X △ 10 m / S2 distance: (x + 300) m speed: (x + 300) 20 m / S



It takes 100 seconds for a train to pass through an 800 meter tunnel and 90 seconds for a train to pass a 650 meter bridge at the same speed


1. (800-650) / (100-90) = 15m / s, train speed
2. 15 × 100-800 = 700m, or 15 × 90-650 = 700m, train length