Fast, fast, 1. If (a-b) × 0.5 = 1.2, a △ 0.2 = 12, then B = () 2. To make the equation "number + Learning" × (number + Learning) = mathematics "hold, then the number represented by" number "is (), and the number represented by" learning "is () 3. One and a quarter × 17.6 + 36 △ four fifths + 2.64 × 12.5= four

Fast, fast, 1. If (a-b) × 0.5 = 1.2, a △ 0.2 = 12, then B = () 2. To make the equation "number + Learning" × (number + Learning) = mathematics "hold, then the number represented by" number "is (), and the number represented by" learning "is () 3. One and a quarter × 17.6 + 36 △ four fifths + 2.64 × 12.5= four

1. If (a-b) × 0.5 = 1.2, a △ 0.2 = 12, then B = (0). 2. To make the equation "(number + Learning) × (number + Learning) = mathematics" hold, then the number represented by "number" is (8), "learning" is (1). 3. One and a quarter × 17.6 + 36 △ four fifths + 2.64 × 12

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It takes four hours for a car to go back and forth between station a and station B, 45 km to go back and 30 km to come back. How many km is the distance between the two stations?

If the time to go is t, then the time to return is 4-T, then 45t = 30 (4-T) solution is t = 1.6s = 45t = 72km, 45 / 30 = 1.5, the speed to go is 1.5 times of the time to return, which is equal to 1.5 times of the time to go, then the total time to go back and forth is 1 + 1.5 = 2.5 times of the time to go one way, and the time to go back and forth is 4 hours, except 2.5 times

Who can help me with the following math problems
(A2 + B2) (A2 + b2-8) + 16 = 0, find the value of A2 + B2
If 1 + X + x2 + X3 = 0, find x + x2 + X3 + +The value of x2ooo

(A2 + B2) (A2 + b2-8) + 16 = 0 (A2 + B2) & sup2; - 8 (A2 + B2) + 16 = 0 (A2 + b2-4) & sup2; = 0a2 + B2 = 41 + X + x2 + X3 = 0 (1 + x) + (X & sup2; + X & sup3;) = 0 (1 + x) + X & sup2; (1 + x) = 0 (1 + X & sup2;) (1 + x) = 0 (1 + X & sup2;) ≥ 0, (1 + X & sup2;) ≥ 1, i.e. (1 + x) = 0 x = - 1 x + X + X