1. A section of road AB is 240 meters long. A starts from a to B. half an hour later, B starts from B to a at the speed of 36 km / h. When a and B meet, the time ratio of a and B is 6:5, 2. The price ratio of a and B is 7:3. After the price rises by 70 yuan, the price ratio is 7:4. How much is the original price of a and B? 3. There are two kinds of apples, the price ratio is 5:4 and the weight ratio is 2:3. After mixing the two kinds of apples into 100kg, the unit price is 4.4 yuan per kg. How much is the original unit price? It's better to solve it by arithmetic

1. A section of road AB is 240 meters long. A starts from a to B. half an hour later, B starts from B to a at the speed of 36 km / h. When a and B meet, the time ratio of a and B is 6:5, 2. The price ratio of a and B is 7:3. After the price rises by 70 yuan, the price ratio is 7:4. How much is the original price of a and B? 3. There are two kinds of apples, the price ratio is 5:4 and the weight ratio is 2:3. After mixing the two kinds of apples into 100kg, the unit price is 4.4 yuan per kg. How much is the original unit price? It's better to solve it by arithmetic


1. Let the velocity be X,
(0.5+(240-0.5x)/(x+36))/((240-0.5x)/(x+36) = 6/5
The solution of the equation is x = 50
2. If the price of Party A and Party B is 7x and 3x respectively, then:
(7x+70):(3x+70)=7:4,
The solution of the equation is: x = 30,
The original price of a: 7 * 30 = 210 yuan,
B original price: 3 * 30 = 90 yuan
3. Suppose the price is 5x, 4x and the weight is 2Y, 3Y respectively, then:
2Y + 3Y = 100, y = 20, so the weight is 40, 60,
40*5x+60*4x=100*4.4,x=1,
So:
The price of big apple is: 5 * 1 = 5 (yuan / kg),
The price of small apple is: 4 * 1 = 4 (yuan / kg)