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The composition of a hydrocarbon is C15H24, and its molecular structure is very symmetrical. It is proved that there are only three groups in the hydrocarbon: vinyl (-CH=CH2) methylene (-CH2 The composition of a hydrocarbon is C15H24, and the molecular structure is very symmetrical. The experiment proves that there are only three groups in the hydrocarbon: Vinyl (-CH=CH2) methylene (-CH2-) methylene () And the vinyl and the methylene must be linked by methylene. When the hydrocarbon is a monocyclic structure, the vinyl in the molecule And the number of methylene groups is A.2,3 B.3,3 C.4,6 D.3,6
The answer is D.
1,3,5-Tripropylene cyclohexane.
First, we can calculate the unsaturation =(2*15+2-24)/2=4, so there are three carbon-carbon double bonds ---> three vinyl groups besides one ring.
And the vinyl and methylene groups are joined together, so just nine C's are gone, and six rings are left.
To be absolutely symmetrical, the group is placed at position 1,3,5.
Hope it helps you!
The compound composed of -CH3,-COOH,-OH,-C6H5 can react with appropriate amount of NaOH, and the product obtained after the reaction can also react with CO2 through ~
:CH3COOH,HOCOOH,C6H5COOH,C6H5OH, capable of reacting with NaOH
After reaction,:CH3COONa,Na2CO3,C6H5COONa,C6H5ONa are generated respectively
After that, CO2 can react with:Na2CO3,C6H5ONa
So that original compound is HOCOOH, or C6H5OH,
:CH3COOH,HOCOOH,C6H5COOH,C6H5OH, capable of reacting with NaOH
After reaction,:CH3COONa,Na2CO3,C6H5COONa,C6H5ONa are generated respectively
After the introduction of CO2 the reaction is:Na2CO3,C6H5ONa
So that original compound is HOCOOH, or C6H5OH,
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