Given a+b2-4a-2b+5=0, the value of root a+b/root 3-2 root 2 is?

Given a+b2-4a-2b+5=0, the value of root a+b/root 3-2 root 2 is?

A2+b2-4a-2b+5=0
(A2-4a+4)+(b2-2b+1)=0
(A-2)2+(b-1)2=0
(A-2)2>=0,(b-1)2>=0
A=2, b=1
Root a+b/Root 3-2Root 2=
√2+1/√3-2√2=√3/3-√2

Given a square +b square -4a-2b+5=0, find the value of 2 roots a+b+1 part root a+b

Solve from a square +b2-4a-2b+5=0 to obtain a2+b2-4a-2b+5=0, i.e. a2-4a+b2-2b+5=0, i.e. a2-4a+4+b2-2b+1=0, i.e.(a-2)2+(b-1)2=0, i.e. a=2, b=1, i.e.2 pieces of root a+b+1, i.e. a+b=2 pieces of root 2+1+1, i.e.2 pieces of root 2+1=√(...