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The simplified re-calculation: Given A=4a2+5b, B=-3a2-2b, find the value of 2A-B, where a=-2, b=1. Let A=4a2+5b, B=-3a2-2b, and find the value of 2A-B, where a=-2, b=1.
A=4a2+5b, B=-3a2-2b,
2A-B=2(4a2+5b)-(-3a2-2b),
=8A2+10b+3a2+2b,
=11A2+12b,
Substitute a=-2, b=1 into the original equation=11×(-2)2+12×1=56.
There is a regular array of algebraic expressions b,2b-a,3b-2a,4b-3a,5b-4a. (1) The law expressed in words is (2) If the value of the fourth algebraic expression is 8, the sum of the first seven algebraic expressions is
The nth term is equal to the product of n times b minus n minus one and a
Sum of the first seven algebraic expressions b+2b-a+3b-2a+4b-3a+5b-4a+6b-5a+7b-6a
=(1+2+…… +7) B-(1+2+…… +6) A
=28B-21a
=7*(4B-3a)
=7*8
=56
The nth term is the product of n times b minus n minus one and a
Sum of the first seven algebraic expressions b+2b-a+3b-2a+4b-3a+5b-4a+6b-5a+7b-6a
=(1+2+…… +7) B-(1+2+…… +6) A
=28B-21a
=7*(4B-3a)
=7*8
=56
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